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This lesson provides a comprehensive guide to understanding algebraic expressions, a cornerstone in the field of algebra. It introduces you to the basic elements like variables, which represent unknown quantities, and constants, which are fixed numbers. The lesson also explains the importance of coefficients, the numbers that multiply variables. Through real-world examples, such as calculating income or game scores, it shows how these elements are combined through mathematical operations like addition and subtraction to form algebraic expressions. The aim is to equip you with the skills to write and manipulate these expressions, making it easier to solve problems in academics and everyday life.
Show less Show more expand_more| Student Learning Objectives: |
|---|
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| | 16 Theory slides |
| | 11 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Tearrik is holding a garage sale to raise money.
A variable is a symbol used to represent an unknown quantity. Often, variables represent fixed but unknown numbers. Variables are usually denoted with letters such as x. x+1=8
A variable can be used to represent a quantity that changes. Izabella's income varies depending on the number of hours she works. She receives a fixed salary of$100 per week plus$4 per hour. Izabella's weekly income could be different every week, depending on the number of hours she works. Therefore, the use of a variable is appropriate. Let x be the hours that Izabella works in a week. Her income can be written by adding the fixed $100 to the $4 per hour.
Izabella's Weekly Income 4x+100When working with variables, numbers are often used to complete mathematical expressions. Two common types of numbers are coefficients and constants.
A coefficient always multiplies a variable, even if the variable is raised to some power. 5x 2x^3 A variable with a coefficient of 1 is usually written without a coefficient.
1x^2 = x^2Another type of number that appear with variables is called constants.
A constant is usually added to or subtracted from a variable. Consider the following example. x + 15
Here, 15 is a constant. Not every constant is written with digits. Some special constants are written with special symbols, such as the number pi, which is often written as π .The applet below displays different variables multiplied by coefficients. Answer the indicated question correctly.
An algebraic expression is a valid combination of numbers, variables, and mathematical operations. For example, in the expression 2x+3, the variable x is being multiplied by its coefficient 2, and this product is then added to the constant 3.
Algebraic expressions are made by adding or subtracting smaller expressions called terms.
+or
-signs.
| Mathematical Expression | Number of Terms | Terms |
|---|---|---|
| 7x | 1 | 7x |
| 8 | 1 | 8 |
| 8x - 2(5) | 2 | 8x and -2(5) |
| x^2 + y^2 +4 | 3 | x^2, y^2, and 4 |
| 2x^2 -5x - 122 | 3 | 2x^2, -5x, and -122 |
Tearrik is selling some of his old shirts and pants.
He is selling the pants for $1 more than three times the price of a shirt. If the price of a shirt is s, write an algebraic expression for the price of a pair of pants.
+or
-signs. In verbal expressions, some words or phrases may imply certain math operations.
| Key Words and Phrases | |
|---|---|
| Addition | added to, plus, sum of, more than, increased by, total of and |
| Subtraction | subtracted from, minus, difference of, less than, decreased by, fewer than, take away |
| Multiplication | multiplied by, times, product of, twice |
| Division | divided by, quotient of |
The price of a shirt is represented by the variable s. We can identify the operations we need by examining the given information. Tearrik is selling the pants for $1 more than three times the price of a shirt. The phrase more than indicates an addition, so we will add $1 to some other quantity. 1 + The phrase three times represents a multiplication. In this case, it is 3 times the price of a shirt s. 1 + 3s There is no more information to include, so this expression represents the price of a pair of pants. 1+3s
Magdalena is playing a video game.
In the game, players are given bonus points for completing challenges quickly.
Help Magdalena write the information as an algebraic expression. Let the variable be t.
+or
-signs. In verbal expressions, there are words or phrases that indicate certain mathematical operations.
| Key Words and Phrases | |
|---|---|
| Addition | added to, plus, sum of, more than, increased by, total of and |
| Subtraction | subtracted from, minus, difference of, less than, decreased by, fewer than, take away |
| Multiplication | multiplied by, times, product of, twice |
| Division | divided by, quotient of |
Let's find some of these keywords. The bonus points are half the difference between400 and the time it took to finish the challenge The half indicates a division by 2 and the difference indicates a subtraction. Magdalena says to take half the difference, so let's write the difference first. This difference can be written by subtracting the time t from 400. 400 - t The division by 2 affects the result of the subtraction. In the order of operations, division operations are evaluated before subtraction. To evaluate the subtraction first, we can write it inside parentheses. 1/2(400 - t) This expression can help Magdalena determine how many bonus points she will get for completing a challenge.
Evaluating an expression consists of determining the value of an expression when the variable or variables of the expression take a specific value. This is done by substituting the given value for the variable in question into the expression and then simplifying it. Consider the following expression. (x-1)^2/2 We will evaluate this expression when x is equal to 5. There are two steps to follow.
After the substitution, the variable disappeared and the algebraic expression turned into a numeric expression.
When x=5, the given expression equals 8.
In a video game, players can collect stars on each level to earn a bonus.
There are three special stars per level. If x is the number of levels, write an expression for the numbers of stars in the game.
There are 73 levels in the game. Use the expression from Part A to find the total number of stars in the game.
The number of stars per level indicates a multiplication.
Substitute the given value for the variable and evaluate the expression.
We can find the total number of bonus stars by adding together the number of stars on every level. Every level has 3 stars. We do not know how many levels there are, so we represent this number with the variable x. Adding the number of stars of every level is the same as multiplying 3 by the number of levels x.
3+ 3+...+ 3_x= 3x
Now we know that there are 73 levels in the game. This means that in our algebraic expression, x is 73.
x = 73 Let's evaluate our algebraic expression from Part A to find the total number of stars in the game. Substituting the value for the variable changes the algebraic expression into a numerical expression because it eliminates the variable entirely.
There are 219 bonus stars in the game.
Consider a square with side length s.
Write an algebraic expression for the difference between the area of the square and its perimeter.
If the side length of the square is 7, find the difference between its area and its perimeter.
The area of a square is the square of the length of a side. The perimeter of a square is the sum of the lengths of all four sides.
Evaluate the algebraic expression from Part A when s=7.
Let's start by recalling the formulas for the area and the perimeter of a square. The area of a square is given by the square of a side. The given square has a side length of s.
Area of the Square: s^2 The perimeter, on the other hand, is found by adding the lengths of all sides of a figure. Since the four sides of the square all have a length of s, the perimeter is found by multiplying s by 4. Perimeter of the Square: 4s Then, to find the difference between these two values, we subtract the perimeter from the area. s^2- 4s
The side length s of the square is 7. Then, to find the difference between the area and the perimeter, let's evaluate the expression for the difference when s= 7.
s= 7
Calculate power
Multiply
Subtract terms
The difference between the area and the perimeter of the given square is 21.
Tearrik is selling some old clothes at a garage sale.
Write an algebraic expression for the total amount of money Tearrik made from selling s shirts and p pairs of pants.
If Tearrik sold 10 shirts and 4 pairs of pants, how much did he make?
How much money Tearrik would make from each type of clothing sold? Add these amounts to find the total.
Substitute the appropriate values for the variables in the expression. Then, evaluate.
The total amount of money Tearrik made is the sum of what he got from selling shirts and pants.
Since he is selling shirts for $ 5 each and he sold s shirts, the amount of money Tearrik made from the shirts can be written as the product of 5 and s. 5* s
Similarly, if p represents the number of pairs of pants sold, then the money made from selling the pants is 16p. 16* p
Finally, let's combine the two expressions to find the total amount of money Tearrik made from these clothes. 5 s + 16 p
We can find the amount of money that Tearrik made from selling 10 shirts and 4 pairs of pants by evaluating the expression.
Evaluate 5 s +16 p when s = 10 and s = 4 Substitute the values for the corresponding variables and find the value of the resulting numerical expression.
s= 10, p= 4
Multiply 5 by 10
Multiply 16 by 4
Add terms
Tearrik made a total of $114 from the shirts and pants sold.
Evaluate the given algebraic expression for the given values. a = 5 & b = 1/2 [0.8em] c = 2 & d = 14
Tearrik's parents decided to give him money based on what he made from selling his things at a garage sale. We do not know how much money Tearrik made from the sale itself, so we can use a variable to represent ti. Consider x as the money Tearrik made at his sale. Money From the Garage Sale: x Consider what Tearrik's parents said about how much money they would give him. Phrases in this plan will indicate the necessary operations for writing the information as an algebraic expression. Double the money Tearrik made and add an additional $5 extra. The word double indicates multiplication by 2, so we will multiply x by 2. 2x Add indicates addition, so we will add $ 5 to double the money Tearrik made. 2x + 5
Now we have an expression for the total amount of money Tearrik will get from his garage sale, even though we do not know exactly how much money he made from the sales directly. Algebraic expressions are great for writing mathematical ideas easily.
Write an algebraic expression for the following phrase. 17 times the number w
First, let's remember that an algebraic expression is a combination of numbers, variables, and mathematical operations. The terms are separated by +
or -
signs. There are words or phrases that imply math operations.
| Key Words and Phrases | |
|---|---|
| Addition | added to, plus, sum of, more than, increased by, total of and |
| Subtraction | subtracted from, minus, difference of, less than, decreased by, fewer than, take away |
| Multiplication | multiplied by, times, product of, twice |
| Division | divided by, quotient of |
Let's take a look at the given phrase. We can already see that the variable is w and that there is an operation involving the number 17. 17 timesthe number w Notice that the phrase includes the word times. This word indicates a multiplication. Now we can write the algebraic expression. 17 * w Now we have the algebraic expression. Good job!
Consider the following algebraic expression. t/11 - 6* 9 How many terms does the expression have?
We are given the following algebraic expression. t/11 - 6* 9 We want to determine the number of terms in the expression. First, let's recall the definition of a term.
Each part of an expression that is separated by a plus sign or a minus sign is called a term.
In the given expression, we see that there are 2 parts separated by a minus sign.
This means that the given expression has two terms, t11 and 6* 9.
We want to identify the variable in the following algebraic expression. x(5+1) + 10.3 A variable represents a quantity that can change and it is usually represented by a letter. Our expression contains a letter x which represents a variable.
There is no other variable in the expression. That means the only variable is x. We did it!
This time we need to identify the constant term of the algebraic expression. A constant is a term without a variable. In our expression, the rightmost number is a good candidate for this.
This term is not a variable nor does it contain an operation. It is a rational number. This indicates that 10.3 is the constant term. We should keep in mind that other numbers in the expression, like 5 and 1, are not constant terms because they are multiplied by the variable x.
Evaluate the algebraic expression considering that x=5 and y=8. 2x^2 - 6y
We want to evaluate the given algebraic expression when the variables x and y are 5 and 8, respectively. 2x^2 - 6y The first step to evaluate an expression is to substitute the values for the corresponding variables. Then, the resulting numerical expression is evaluated following the order of operations. In this case, we will substitute x= 5 and y= 8. Let's do it!
The value of the given expression is 2 when x=5 and y=8. Remember that we should be careful when substituting the values for the variables to avoid substituting a value for the incorrect variable.
Complete the following table.
| z | 4z + 19 |
|---|---|
| 3 | |
| 6 | |
| 9 |
Write the values from least to greatest.
The table gives an algebraic expression and some values for the variable z. Algebraic Expression: & 4z+19 Values ofz: & 3, 6, 9 Let's evaluate the expression for those values of z. This is done by substituting 3, 6, and 9 for z in the given expression and then evaluate. Let's start with 3. Remember to follow the order of operations.
We can do the same for the rest of the values. Let's write these substitutions on a table.
| z | Evaluation | 4z + 19 |
|---|---|---|
| 3 | 4* 3 + 19 | 31 |
| 6 | 4* 6 + 19 | 43 |
| 9 | 4* 9 + 19 | 55 |
After evaluation, the values are 31, 43, and 55. Good job!