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| Student Learning Objectives: |
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| | 12 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Here are a few practice exercises before getting started with this lesson.
Calculate the value of the following expressions. Write the answer as an integer number or as a fraction in its simplest form.
Simplify.
The exponent of an expression indicates how many times the base is multiplied by itself.
| Power | Multiplication | Value |
|---|---|---|
| 4^2 | 4* 4 | 16 |
| 2^3 | 2* 2* 2 | 8 |
| 5^4 | 5* 5* 5* 5 | 625 |
| 1^5 | 1* 1* 1* 1* 1 | 1 |
By definition, to calculate the value of a power, the base is multiplied by itself as many times as indicated by the exponent. So, what happens with expressions where the exponent is a rational number, such as 2^(13)? It might be confusing to multiply 2 by itself 13 times. 2^(13)=2 * ? Considering the Power of a Power Property, notice what happens when the expression 2^(13) is raised to the third power.
2^(13)=sqrt(2)
The relationship between rational exponents and roots can be extended to any rational exponent of the form 1n, where n is a natural number.
For any real number a and natural number n, the expression a^(1n) is defined as the n^(th) root of a. Note that a root with an even index is defined only for non-negative numbers. Therefore, if n is even, then a must be non-negative.
Dominika pays 625^(14) dollars per hour to study with a private tutor.
As her first homework assignment, she was given the task of writing how much she pays per hour as a radical. Write her answer without including the currency symbol.
Calculate the values of the given powers with rational exponents by using a radical.
YBC 7289 is an ancient Babylonian clay tablet believed to be the work of a student who lived in southern Mesopotamia around the year 1700BC. The tablet contains an extremely accurate approximation of the length of the diagonal of a square with side length 1.
Here, the length of both legs is 1. Therefore, by substituting a= 1 and b= 1 into the Pythagorean Theorem, the length of the diagonal c can be found.
a= 1, b= 1
1^a=1
Add terms
sqrt(LHS)=sqrt(RHS)
sqrt(a^2)=a
Rearrange equation
The length of the diagonal, written as a radical, is exactly sqrt(2) units. This number can be also expressed as a power with a rational exponent of 12.
Note that the numerator of a rational number does not have to be 1, but could also be any integer number. Therefore, rational numbers with a numerator different than 1 should also be considered as rational exponents.
When a number is raised to the power of a fraction, that fraction is the number's rational exponent. Such an expression is equivalent to a root.
Using the Power of a Power Property, another expression equivalent to a^()mn involving a radical can be found.
a^(mn) = sqrt(a^m) or a^(mn) = (sqrt(a))^m
Ignacio ate some cake at a birthday party. When he arrived home, he told his parents that he had 8^(23) slices.
His mother, who is a math teacher, asked him to express the number of slices that he ate as a radical.
Now Ignacio is able to give an answer for his mother. He can say that he ate sqrt(64) slices of the cake. To answer his father, Ignacio needs to find the value of the found radical.
Now, focus on roots with an even index. For example, consider sqrt(3). By definition, sqrt(3) is a number that, when raised to the second power, equals 3. (sqrt(3))^2=3 What about all the numbers that are equal to 3 when raised to the second power? There are two such numbers, sqrt(3) and - sqrt(3). x^2=3 ⇒ lx=sqrt(3) or x=- sqrt(3)
To avoid complicating the definitions of a^(1n) and a^(mn), positive sqrt(3) is conventionally defined as the principal root. Therefore, for any even number n, sqrt(a) is defined as the positive number that, when raised to the nth power, equals a.It is important to know how to write expressions with rational exponents as radicals. Sometimes it is required to simplify an expression by using only radicals. Consider the following example. Simplify the expression and rewrite it using radicals only. 3^(35)* 2^(15)
a^(mn)=sqrt(a^m)
a^(1n)=sqrt(a)
sqrt(a)*sqrt(b)=sqrt(a* b)
Calculate power
Multiply
sqrt(a)=a^(12)
a^m*a^n=a^(m+n)
a/b=a * 2/b * 2
a/b=a * 3/b * 3
Add fractions
Does the following equation have any real solutions? If yes, write those solutions. x=x^(15)
To solve the equation, we will start by rewriting its right-hand side as a root. Then we can raise both sides of the equation to the power of 5.
Now, we can write all the terms on the left-hand side and factor the resulting expression. Then we can use the Zero Product Property to find the roots of the expression.
The solutions to the equation are x=- 1, x=0, and x=1.
One way to look for solutions using a graph is to consider each side of the equation as a function. The functions can be graphed on the same coordinate plane, and any points of intersection will be the solutions.
The graphs intersect at x=-1, x=0, and x=1.