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| Student Learning Objectives: |
|---|
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| | 12 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Here are a few practice exercises before getting started with this lesson.
Calculate the value of the following expressions. Write the answer as an integer number or as a fraction in its simplest form.
Simplify.
The exponent of an expression indicates how many times the base is multiplied by itself.
| Power | Multiplication | Value |
|---|---|---|
| 4^2 | 4* 4 | 16 |
| 2^3 | 2* 2* 2 | 8 |
| 5^4 | 5* 5* 5* 5 | 625 |
| 1^5 | 1* 1* 1* 1* 1 | 1 |
By definition, to calculate the value of a power, the base is multiplied by itself as many times as indicated by the exponent. So, what happens with expressions where the exponent is a rational number, such as 2^(13)? It might be confusing to multiply 2 by itself 13 times. 2^(13)=2 * ? Considering the Power of a Power Property, notice what happens when the expression 2^(13) is raised to the third power.
2^(13)=sqrt(2)
The relationship between rational exponents and roots can be extended to any rational exponent of the form 1n, where n is a natural number.
For any real number a and natural number n, the expression a^(1n) is defined as the n^(th) root of a. Note that a root with an even index is defined only for non-negative numbers. Therefore, if n is even, then a must be non-negative.
Dominika pays 625^(14) dollars per hour to study with a private tutor.
As her first homework assignment, she was given the task of writing how much she pays per hour as a radical. Write her answer without including the currency symbol.
Calculate the values of the given powers with rational exponents by using a radical.
YBC 7289 is an ancient Babylonian clay tablet believed to be the work of a student who lived in southern Mesopotamia around the year 1700BC. The tablet contains an extremely accurate approximation of the length of the diagonal of a square with side length 1.
Here, the length of both legs is 1. Therefore, by substituting a= 1 and b= 1 into the Pythagorean Theorem, the length of the diagonal c can be found.
a= 1, b= 1
1^a=1
Add terms
sqrt(LHS)=sqrt(RHS)
sqrt(a^2)=a
Rearrange equation
The length of the diagonal, written as a radical, is exactly sqrt(2) units. This number can be also expressed as a power with a rational exponent of 12.
Note that the numerator of a rational number does not have to be 1, but could also be any integer number. Therefore, rational numbers with a numerator different than 1 should also be considered as rational exponents.
When a number is raised to the power of a fraction, that fraction is the number's rational exponent. Such an expression is equivalent to a root.
Using the Power of a Power Property, another expression equivalent to a^()mn involving a radical can be found.
a^(mn) = sqrt(a^m) or a^(mn) = (sqrt(a))^m
Ignacio ate some cake at a birthday party. When he arrived home, he told his parents that he had 8^(23) slices.
His mother, who is a math teacher, asked him to express the number of slices that he ate as a radical.
Now Ignacio is able to give an answer for his mother. He can say that he ate sqrt(64) slices of the cake. To answer his father, Ignacio needs to find the value of the found radical.
Now, focus on roots with an even index. For example, consider sqrt(3). By definition, sqrt(3) is a number that, when raised to the second power, equals 3. (sqrt(3))^2=3 What about all the numbers that are equal to 3 when raised to the second power? There are two such numbers, sqrt(3) and - sqrt(3). x^2=3 ⇒ lx=sqrt(3) or x=- sqrt(3)
To avoid complicating the definitions of a^(1n) and a^(mn), positive sqrt(3) is conventionally defined as the principal root. Therefore, for any even number n, sqrt(a) is defined as the positive number that, when raised to the nth power, equals a.It is important to know how to write expressions with rational exponents as radicals. Sometimes it is required to simplify an expression by using only radicals. Consider the following example. Simplify the expression and rewrite it using radicals only. 3^(35)* 2^(15)
a^(mn)=sqrt(a^m)
a^(1n)=sqrt(a)
sqrt(a)*sqrt(b)=sqrt(a* b)
Calculate power
Multiply
sqrt(a)=a^(12)
a^m*a^n=a^(m+n)
a/b=a * 2/b * 2
a/b=a * 3/b * 3
Add fractions
Consider the following sphere.
What is the radius r of a sphere with volume 4π cubic centimeters? Write the answer in exact form.
The volume V of a sphere is calculated by multiplying 43 by π times the cube of the radius. V=4/3π r^3 We are given that the volume of the sphere is 4π. Therefore, by substituting 4π for V, we can apply inverse operations to solve for the radius of the sphere r.
When the radius is sqrt(3) centimeters, the sphere has a volume of 4π cubic centimeters.
Zosia simplified the numeric expression 64^(32). However, according to her teacher, she made a mistake in one of the steps. In what step was a mistake made? Step1& 64^(32) [0.1em] Step2& (sqrt(64))^2 [0.1em] Step3& 4^2 [0.1em] Step4& 16
We will look at the steps one at a time.
In Step 1, Zosia has copied the numeric expression correctly, so no mistake was made here. Step1 64^(32) ✓
Here, Zosia expressed the power with a rational exponent as a root. However, she wrote the numerator of the exponent as the index of the root and the denominator as the exponent. This is her mistake. rcc Step1& 64^(32)& ✓ [0.1em] Step2& (sqrt(64))^2 & * Let's correct Zosia's mistake. Recall that when we rewrite a power with a rational exponent as a root, the numerator and denominator of the rational exponent are the index of the root and the exponent of the expression, respectively. rcc Step1& 64^(32)& ✓ [0.1em] Step2& (sqrt(64))^3 & ✓
Here, Zosia calculated the cube root of 64 to be 4. No mistake was made here, but since she made a mistake in the second step, she should have calculated the square root of 64 instead. Let's continue with the correct calculation. Step1& 64^(32) [0.1em] Step2& (sqrt(64))^3 [0.1em] Step3& 8^3
What happens in this last step is similar to what happens in the third step. No mistake is made in the calculation itself, but because of the mistake made previously, the number to be calculated is incorrect. The final calculation should be 8^3, not 4^2. Step1& 64^(32) [0.1em] Step2& (sqrt(64))^3 [0.1em] Step3& 8^3 [0.1em] Step4& 512 The final simplification of 64^(32) is 512, not 16.
Using a rational exponent, write an expression for the side length of the square.
The area of a square is calculated by squaring the side length. If the side length of the square is s, we can write the following equation. A=s^2 The area of this square is x square centimeters. By substituting this variable into the formula, we can determine the length of the side.
We only consider the principal root because a polygon cannot have a negative side length. Now, since we are asked to write the answer using a rational exponent, we need to rewrite the radical expression.
As shown, we have found that the side length is x^(12) square centimeters.