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| 13 Theory slides |
| 12 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Before any theorems will be introduced, try to discover some properties of angles using the interactive applet. While exploring, think about how those properties could be proven. The applet allows for translations and rotations of the angles. Consider a pair of vertical angles.
Vertical angles can be mapped onto each other by using a rotation. Since rotations are rigid motions, the angle measures are preserved. This leads to the following theorem.
Vertical angles are always congruent.
Based on the characteristics of the diagram, the following relations hold true.
∠1≅∠3
∠2≅∠4
Analyzing the diagram, it can be seen that ∠1 and ∠2 form a straight angle, so these are supplementary angles. Similarly, ∠2 and ∠3 are also supplementary angles.
Therefore, by the Angle Addition Postulate, the sum of m∠1 and m∠2 is 180∘, and the sum of m∠2 and m∠3 is also 180∘. These facts can be used to express m∠2 in terms of m∠1 and in terms of m∠3.
Angle Addition Postulate | Isolate m∠2 |
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m∠1+m∠2 = 180∘ | m∠2 = 180∘−m∠1 |
m∠2+m∠3 = 180∘ | m∠2 = 180∘−m∠3 |
The previous proof can be summarized in the following two-column table.
0. 0. Statements
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0. 0. Reasons
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1. 1. ℓ1 and ℓ2 lines
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1. 1. Given
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2. 2. ∠1 and ∠2 supplementary
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2. 2. Definition of straight angle
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3. 3. m∠1+m∠2=180∘
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3. 3. Definition of supplementary angles
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4. 4. m∠2=180∘−m∠1
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4. 4. Subtraction Property of Equality
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5. 5. ∠2 and ∠3 supplementary
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5. 5. Definition of straight angle
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6. 6. m∠2+m∠3=180∘
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6. 6. Definition of supplementary angles
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7. 7. m∠2=180∘−m∠3
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7. 7. Subtraction Property of Equality
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8. 8. 180∘−m∠1=180∘−m∠3
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8. 8. Transitive Property of Equality
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9. 9. m∠1=m∠3
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9. 9. Subtraction and Multiplication Properties of Equality
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Consider the points A, B, C, and D on each ray that starts at the point of intersection E of the two lines.
Use the given expressions to form an equation for x. Identify the relationship between ∠1 and ∠3, as well as ∠2 and ∠4 by analyzing their positions.
x=19 | |
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m∠1=3x+14 | m∠2=6x−5 |
m∠1=3(19)+14 | m∠2=6(19)−5 |
m∠1=57+14 | m∠2=114−5 |
m∠1=71∘ | m∠2=109∘ |
Consider two parallel lines cut by a transversal. The applet shows a pair of corresponding angles, ∠A and ∠B. Is it possible to translate one line so that one of these angles maps onto another?
The observed relation between corresponding angles is presented and proven in the following theorem.
If ℓ1∥ℓ2, then ∠1≅∠5, ∠2≅∠6, ∠3≅∠7, and ∠4≅∠8.
Note that the converse statement is also true.
If ∠1≅∠5, ∠2≅∠6, ∠3≅∠7, or ∠4≅∠8, then ℓ1∥ℓ2.
This theorem can be proven by an indirect proof. Let ℓ1 and ℓ2 be two lines intersected by a transversal line ℓ3 forming corresponding congruent angles ∠1 and ∠2.
In a Flowerland Village house, there are stairs with hand railings like shown in the diagram. The measures of ∠1 and ∠2 are expressed as 5t−2 and 4t+12, respectively.
How do measures of ∠1 and ∠2 relate to each other? Use the given expressions to form an equation for t.
Like corresponding angles, alternate interior angles are also formed by two parallel lines cut by a transversal.
If ℓ1∥ℓ2, then ∠1≅∠2 and ∠3≅∠4.
To prove that alternate interior angles are congruent, it will be shown that ∠1 and ∠2 are congruent.
The previous proof can be summarized in the following two-column table.
0. 0. Statements
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0. 0. Reasons
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1. 1. ∠2 and ∠5 are vertical angles
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1. 1. Def. of vertical angles
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2. 2. ∠2≅∠5
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2. 2. Vertical Angles Theorem
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3. 3. ∠5 and ∠1 are corresponding angles
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3. 3. Def. of corresponding angles
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4. 4. ∠5≅∠1
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4. 4. Corresponding Angles Theorem
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5. 5. ∠2≅∠1
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5. 5. Transitive Property of Congruence
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Apart from the points of intersection, consider two more points on each line.
The converse statement is also true.
If ∠1≅∠2 or ∠3≅∠4, then ℓ1∥ℓ2.
The proof will be based on the given diagram, but it holds true for any pair of lines cut by a transversal. Consider only one pair of congruent alternate interior angles and one more angle.
Converse Corresponding Angles Theorem |
If two lines are cut by a transversal so that the corresponding angles are congruent, then the lines are parallel. |
Since ∠1 and ∠α are corresponding congruent angles, then ℓ1 and ℓ2 are parallel lines. To summarize, all of the steps will be described in a two-column proof.
0. 0. Statement
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0. 0. Reason
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1. 1. ∠1≅∠2
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1. 1. Given
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2. 2. ∠2≅∠α
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2. 2. Vertical Angles Theorem
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3. 3. ∠1≅∠α
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3. 3. Transitive Property of Congruence
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4. 4. ℓ1∥ℓ2
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4. 4. Converse Corresponding Angles Theorem
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Similar properties can be discovered for alternate exterior angles.
If ℓ1∥ℓ2, then ∠1≅∠2 and ∠3≅∠4.
In order to prove that alternate exterior angles are congruent, it will be shown that ∠1 and ∠2 are congruent.
The previous proof can be summarized in the following two-column table.
0. 0. Statements
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0. 0. Reasons
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1. 1. ∠2 and ∠8 are corresponding angles
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1. 1. Def. of corresponding angles
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2. 2. ∠2≅∠8
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2. 2. Corresponding Angles Theorem
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3. 3. ∠8 and ∠1 are vertical angles
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3. 3. Def. of vertical angles
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4. 4. ∠8≅∠1
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4. 4. Vertical Angles Theorem
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5. 5. ∠2≅∠1
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5. 5. Transitive Property of Congruence
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Consider the points of intersection as well as two more points on each line.
∠ADB≅∠GFH and ∠CDB≅∠EFH
If ∠1≅∠2 or ∠3≅∠4, then ℓ1∥ℓ2.
The proof will be based on the given diagram, but it holds true for any pair of lines cut by a transversal. Consider only one pair of congruent alternate exterior angles and one more angle.
Converse Corresponding Angles Theorem |
If two lines are cut by a transversal so that the corresponding angles are congruent, then the lines are parallel. |
Since ∠1 and ∠α are corresponding congruent angles, ℓ1 and ℓ2 are parallel lines. Each step of the proof will now be summarized in a two-column proof.
0. 0. Statement
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0. 0. Reason
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1. 1. ∠1≅∠2
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1. 1. Given
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2. 2. ∠2≅∠α
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2. 2. Vertical Angles Theorem
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3. 3. ∠1≅∠α
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3. 3. Transitive Property of Congruence
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4. 4. ℓ1∥ℓ2
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4. 4. Converse Corresponding Angles Theorem
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In order to build Tulip Street on the south side of the Lilian river, which goes through Flowerland Village, there is a need to build a bridge. Devontay, an architect, proposed the following plan for the bridge.
It is known that the measure of ∠1 is equal to 4a+11 and the measure of ∠2 is equal to 8a−53. What are the measures of ∠1 and ∠2?
How do the measures of ∠1 and ∠2 relate to each other? Use the given expressions to form an equation for a.
By analyzing the diagram it can be noted that ∠1 and ∠2 are alternate interior angles.
m∠1=4a+11, m∠2=8a−53
LHS−4a=RHS−4a
LHS+53=RHS+53
LHS/4=RHS/4
Rearrange equation
Any point on a perpendicular bisector of a line segment is equidistant from the endpoints of the line segment.
Based on the characteristics of the diagram, CM is the perpendicular bisector of AB. Therefore, C is equidistant from A and B.
AC=BC
Suppose CM is the perpendicular bisector of AB. Then M is the midpoint of AB.
Consider a triangle with vertices A, M, and C, and another triangle with vertices and B, M, and C.
Both △ACM and △BCM have a right angle and congruent legs AM and BM. Since all right angles are congruent, ∠AMC≅∠BMC. Furthermore, by the Reflexive Property of Congruence, CM is congruent to itself.
By the Side-Angle-Side Congruence Theorem, the triangles are congruent. Therefore, since corresponding parts of congruent figures are congruent, their hypotenuses AC and BC are also congruent. By the definition of congruent segments, AC and BC have the same length. This means that C is equidistant from A and B.
Using this reasoning it can be proven that any point on a perpendicular bisector is equidistant from the endpoints of the segment.
The proof can be summarized in the following two-column table.
0. 0. Statements
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0. 0. Reasons
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1. 1. AM≅MB ∠AMC and ∠BMC are right angles |
1. 1. Definition of a perpendicular bisector.
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2. 2. ∠AMC≅∠BMC
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2. 2. All right angles are congruent.
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3. 3. CM≅CM
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3. 3. Reflexive Property of Congruence.
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4. 4. △ACM≅△BCM
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4. 4. SAS Congruence Theorem.
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5. 5. AC≅BC
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5. 5. Corresponding parts of congruent figures are congruent.
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6. 6. AC=BC
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6. 6. Definition of congruent segments.
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Suppose CM is the perpendicular bisector of AB.
Using the given points A, B, C, and M as vertices, two triangles can be formed. The resulting triangles, △ACM and △BCM, can be proven to be congruent by identifying a congruence transformation that maps one triangle onto the other.
Reflection Across CM | |
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Preimage | Image |
B | A |
C | C |
M | M |
AC=CB⇓CM⊥AB and AM=MB
Consider AB and a point C equidistant from A and B.
Additionally, it was already known that CM and AB are perpendicular.
CM⊥AB and AM=MB
By the definition of a perpendicular bisector, CM is the perpendicular bisector of AB. Therefore, C lies on the perpendicular bisector of AB.
In Flowerland Village, there are two related families, Funnystongs and Cleverstongs, who live opposite each other. Mr. Funnystong and Mr. Cleverstong want to pave a road between the houses so that every point of the road is equidistant to their houses.
Distance: 8 meters from each house.
Direction: Along the perpendicular bisector to the segment with endpoints at the houses.
What does the the Perpendicular Bisector Theorem state?
Recall what the Perpendicular Bisector Theorem states.
Any point on a perpendicular bisector is equidistant from the endpoints of the line segment.
With this theorem in mind, the position of the road can be determined. To do so, draw a segment whose endpoints are located at the houses.
Before drawing the perpendicular bisector of this segment, its midpoint should be found. Since the distance between the houses is 16 meters, the perpendicular bisector will pass through a point that is 216=8 meters away from the houses.
Based on the theorem, it can be said that each point on the bisector is equidistant from the houses. Therefore, the road between the houses should be paved along the segment's perpendicular bisector.
Plane P is the perpendicular bisector of AC.
From the exercise, we know that plane P is the perpendicular bisector of AC. This means that it cuts AC in two equal halves at a right angle. Also, according to the Perpendicular Bisector Theorem we know that AD≅ DC and AB≅ BC. Let's add this information to the diagram.
As we can see, we have two pairs of adjacent sides that are congruent. We also see that the diagonals intersect at a right angle. This fits the definition of a kite. Remember, we have no information about the distance of D and B from E. If we change the position of D somewhat, we see that we can only argue that it can be a kite.
We don't have enough information to classify it as any other type of quadrilateral as this would require us to know information about the opposite sides of the quadrilateral. For example, a parallelogram requires opposite sides to be parallel.
In the following diagram, BD bisects ∠ADE. What is the measure of ∠EDC?
From the diagram, we see that ∠ DAB and ∠ ABD are congruent angles. Let's label the measures of these angles as y. We also know that BD bisects ∠ ADE. If we label m∠ ADE as 2x, we get that m∠ BDA and m∠ BDE are both x.
Examining the diagram, we see that ∠ ABD and ∠ BDE form a pair of alternate interior angles. Since AB∥ DE, we know by the Alternate Interior Angles Theorem that ∠ ABD≅ ∠ BDE. Therefore, we can conclude that x=y. Let's make this switch in the diagram.
Because △ ABD has three congruent angles, it must be an equilateral triangle. Each interior angle of an equilateral triangle measures 60^(∘), which means that y=60^(∘).
We can find m∠ EDC next. Since this angle forms a straight angle with ∠ EDB and ∠ BDA, the measures of these angles add up to 180^(∘).
Heichi is playing a game of pool and it is his turn. The only good option is to try for the 6-ball in the upper left pocket. In order to make the shot, the cue ball has to come off the wall at an angle of 56∘. What must the measure of θ be for this to occur?
When the cue ball hits the wall, the angles created by the path of the ball and a vertical line that can be drawn at the point of impact are congruent. Two examples of this are shown below.
Let's add this piece of information to the pool table and label the congruent angles as α.
Examining the diagram, we can see that the 56^(∘)-angle and α are complementary angles. With this information, we can determine the measure of α. 56^(∘)+α = 90^(∘) ⇓ α = 34^(∘) Let's add this information to the diagram.
Notice that the 34^(∘)-angle that is to the right of the purple segment and θ form a pair of alternate interior angles. Since the two segments are parallel, we know by the Alternate Interior Angles Theorem that they are congruent. Therefore, θ=34^(∘).
Find the values of x and y.
Examining the diagram, we see that 4x-20^(∘) is a corresponding angle to both the 4y-degree angle and 3x-degree angles. Since there are two pairs of parallel lines, we can conclude that the three angles are congruent by to the Corresponding Angles Theorem.
Now we can write two equations, to form a system of equations and solve for the variables. 4y=4x-20^(∘) & (I) 3x=4x-20^(∘) & (II) Let's solve this system by using the Substitution Method. First, we will solve Equation II.