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| 12 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Take a look at the following single-term algebraic expressions. Can a shared characteristic be recognized which would allow for them to be classified reasonably? Drag the expressions and use the colored areas to visualize any common themes, and identify which expressions could be grouped together.
A monomial is an algebraic expression consisting of only one term. It is a product of powers of variables and a constant called the coefficient.
Expression | Why It Is a Monomial |
---|---|
5 | Any constant is a valid monomial. By the Zero Exponent Property, 5x0=5. |
0 | The coefficient of a monomial can be 0. |
-2x5 | The coefficient can be negative. |
5x3y | A monomial can have numbers in the denominator. |
Although they appear to be monomials at first glance, the single-term expressions in the following table do not satisfy the definition of a monomial.
Expression | Why It Is Not a Monomial |
---|---|
2x-1 | The variables of a monomial cannot have negative integer exponents. |
4yx3 | Monomials cannot have variables in the denominator. |
5x3y21 | The variables of a monomial must only have whole number exponents. |
The degree of a monomial is the sum of the exponents of its variable factors. If a variable has no exponent written in it, it is assumed to be 1. Additionally, all nonzero constants have a degree of 0. The constant 0 does not have a degree.
Monomial | Degree |
---|---|
3x | 1 |
x2 | 2 |
9x3 | 3 |
x3y | 4 |
7 | 0 |
13a3b4c5 | 12 |
0 | undefined |
The next applet shows different algebraic expressions. Use the new knowledge introduced previously to determine whether or not these expressions are monomials.
One way that polynomials can be classified is according to the number of terms they have. The following table shows the names used for this classification.
Name | Definition | Example |
---|---|---|
Monomial | A polynomial with a single term. | 3x2y3 |
Binomial | A polynomial with a exactly two terms. | 5xy+3x2y3 |
Trinomial | A polynomial with exactly three terms. | x3−9x+4 |
polynomialis commonly used.
Polynomial | Degree |
---|---|
-5x2y+x2y4−11x2−3 | 6 |
x−11x4+8x3 | 4 |
7 | 0 |
0 | Undefined |
In a polynomial, the coefficient in front of the term with the highest degree is called the leading coefficient.
The following applet alternates between different algebraic expressions. Determine whether or not these expressions are polynomials.
The following applet alternates between different polynomials. Determine the given polynomial's degree or leading coefficient as indicated.
Izabella is improving her understanding of polynomials in her algebra course. However, she has come across some problems where she needs to identify the number of terms of some algebraic expressions and only some of the expressions are polynomials.
For an algebraic expression to be a polynomial, each term must be a valid monomial. A monomial is a single-term expression that is a product of numbers and variables raised to exponents that are whole numbers. Three of the given expressions do not satisfy this definition. That takes them out of the running as being polynomials.
Expression | Reason |
---|---|
4x+x21 | It has a non-integer exponent. |
2x2+5+y-2 | It has a negative exponent. |
2y3x+x2−5y3+9 | It has a variable in the denominator. |
Now that Izabella knows which expressions are polynomials and which are not, she can figure out how to identify their number of terms. Recall that, in any algebraic expression, terms are separated by a plus or a minus sign.
Polynomial | Number of terms |
---|---|
4x−3x3 | 2 |
2x2+5−7y | 3 |
8xy+3x3−3y3+2x | 4 |
Expression | Number of terms |
4x+x21 | 2 |
2x2+5+y-2 | 3 |
2y3x+x2−5y3+9 | 4 |
A polynomial in one variable is expressed in standard form when the monomials that form it are arranged in decreasing degree order. This form can be represented with the following general expression.
anxn+an−1xn−1+⋯+a1x1+a0x0
Izabella, so excited about solving polynomial related problems, has started a study group with Magdalena to work together on another set of polynomials. This time, the polynomials need to be written in standard form and have their characteristics identified.
Classification: Binomial
Degree: 3
Classification: Trinomial
Degree: 5
Factor out x2 & x3
Add and subtract terms
Term | Degree | Coefficient |
---|---|---|
7x2 | 2 | 7 |
x3⇔(1)x3 | 3 | 1 |
Standard Form | ||
---|---|---|
x3+7x2 | ||
Classification | Degree | Leading Coefficient |
Binomial | 3 | 1 |
Commutative Property of Addition
Factor out x & x3
Add and subtract terms
Term | Degree | Coefficient |
---|---|---|
15x⇔15x1 | 1 | 15 |
-8x3 | 3 | -8 |
-2x5 | 5 | -2 |
Standard Form | ||
---|---|---|
-2x5−8x3+15x | ||
Classification | Degree | Leading Coefficient |
Trinomial | 5 | -2 |
Polynomial Equation | Degree |
---|---|
2x3+8x2+2x−12=0 | 3 |
Solutions | |
x=-3,x=-2,x=1 |
The standard form of a polynomial arranges its terms by degree in descending numerical order. Therefore, let's start by arranging the terms accordingly. 6x^2+2x^4-x ⇕ 2x^4 + 6x^2 - x Once the polynomial is in standard form, we can see that 2x^4 is the first term, 6x^2 is the second term, and - x is the third term.
The degree of a polynomial the greatest of the degrees of its terms. Let's begin by highlighting the degrees of each term. 2x^4 + 6x^2 - x ⇕ 2x^4 + 6x^2 - x^1 The terms of the given polynomial have degrees 4, 2, and 1, respectively. Therefore, the degree of the polynomial is 4.
The coefficient that stands in front of the term with the highest degree is the leading coefficient of a polynomial. Alternatively, when written in standard form, the leading coefficient of a polynomial is the constant in front of the first term.
2x^4 + 6x^2 - x
In Part B we identified 2x^4 as the term with the highest degree. Therefore, 2 is the leading coefficient of the polynomial.
To calculate the volume of a sphere, we use the formula V=34πr3. What is the degree of this monomial?
Let's begin by carefully considering the given formula. V=4/3 π r^3 The degree of a monomial is the sum of the exponents of the variables. Remember that π is not a variable. In fact, it represents an irrational number. π = 3.141592... This means that the left two factors of the formula are constants. V= 4/3 π* r^3 Since r is the only variable in the formula, and it is raised to the third power, we can conclude that the degree of the monomial is 3.
Is the following expression a polynomial? Explain your reasoning.
Polynomials are algebraic expressions that can be written as a sum of terms of the following form. any number* x^(whole number) Let's rewrite some of the variable terms and also the constant term. Then, we can check if it follows the description of a polynomial. any number* x^(whole number) ⇓ 9x^5+ 1x^2 - 6.5x^4 - 6x^0 The expression is a polynomial since all terms follow the description of a polynomial.
Looking at the expression, we can see that one of the terms does not match the description of a term contained within a polynomial. any number* x^(whole number) ⇓ 3^x+ 10x^0 As we can see, x is in the exponent of one of the terms, not the base of the exponent. Therefore, this expression is not a polynomial.
Let's first simplify the expression by combining like terms.
The square root of a number can be rewritten as the number raised to the power of 0.5. If we rewrite sqrt(x) in this way, we notice that the expression is not a polynomial. any number* x^(whole number) ⇓ 2x^0+ 1x^(0.5) Since 0.5 is not a whole number, the expression is not a polynomial.
Any expression written in the form 1a^b can be rewritten as a^(- b). Let's rewrite the expression according to this and determine if it is a polynomial. any number* x^(whole number) ⇓ p(x)= 1x^2+ 1(x^2+5)^(- 1) The expression is not a polynomial because - 1 is not a whole number.
What is the degree of the given monomial?
A monomial is defined as a real number, a variable, or a product of a real number and one or more variables where the exponents are whole numbers. The degree of a monomial is the sum of the exponents of its variables. Let's identify all the exponents. 4x ⇔ 4x^1 As we can see, the exponent of the sole variable x is 1. Therefore, the degree of the monomial is 1.
As we did in Part A, let's identify the exponent of the variable of the monomial. 23x^4 We see that the degree of the monomial is 4.
This time the monomial has two variables. Let's identify their exponents. 8m^2n^4 The degrees of m and n are 2 and 4, respectively. We can find the degree of the monomial by adding these exponents. 2+ 4= 6 Therefore, the degree of the monomial is 6.
Again, lets identify the variables in the monomial. 5q^4rs^6 ⇒ 5q^4 r^1 s^6 The exponents of the variables are 4, 1, and 6. Let's add them to find its degree. 4 + 1 + 6 = 11 The degree of the monomial is 11.
Simplify the following polynomial expressions.
When we simplify an algebraic expression, the first step is to identify which terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. ( 5y+ 4)+( - 2y+ 6) In the given expression, we have two y-terms and two constants. To simplify the expression, we will rearrange it using the Commutative Property of Addition and then combine like terms.
Let's start by identifying the like terms.
( -3p^3+ 5p^2 - p)+( 15p - p^2 - p^3)
Now we can simplify the expression by rearranging the terms and combining them.
As in previous parts, we will start by identifying which terms are like terms.
(k^3-7k+ 2)-(k^2 - 12)
We only have two like terms, the constants. Let's simplify the expression. Remember that when we remove a parenthesis with a negative sign in front of it, we must change signs of all terms inside the parenthesis.
...increased the second term's coefficient by 3. |
...decreased the first term's exponent by 4. |
...increased the third term's exponent by 8. |
...decreased the constant by 1. |
The coefficient is the constant that stands in front of a variable term. If we increase the coefficient in front of the second term by 3, we get a new polynomial.
Original Polynomial | New Polynomial |
---|---|
10x^8+x^4+5x-14 | 10x^8+( 3+1)x^4+5x-14 ⇓ 10x^8+4x^4+5x-14 |
The polynomial's degree is the greatest of the degrees of its terms, so changing a constant should not have an effect on the degree of the polynomial. We see that 10x^8 is the variable term with the greatest exponent. Therefore, the degree of the new polynomial is 8 — the same as the original polynomial.
If we decrease the first term's exponent by 4, we get the following new polynomial.
Original Polynomial | New Polynomial |
---|---|
10x^8+x^4+5x-14 | 10x^(8 - 4)+x^4+5x-14 ⇓ 10x^4+x^4+5x-14 ⇓ 11x^4+5x-14 |
The greatest exponent in the polynomial is now 4, which means that the degree of the new polynomial is 4.
The third term is 5x. Notice that we can write this as 5x^1. Let's increase its exponent by 8.
Original Polynomial | New Polynomial |
---|---|
10x^8+x^4+5x-14 | 10x^8+x^4+5x^(1 + 8)-14 ⇓ 10x^8+x^4+5x^9-14 |
Now 5x^9 has the greatest exponent, 9. Therefore, the new polynomial is a ninth-degree polynomial.
We can write the following new polynomial by decreasing the constant by 1.
Original Polynomial | New Polynomial |
---|---|
10x^8+x^4+5x-14 | 10x^8+x^4+5x-14 - 1 ⇓ 10x^8+x^4+5x-15 |
The constant will not change the degree of the polynomial. Therefore, the polynomial is still of degree 8.