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| 12 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Geometric Transformations and Similarity:
Triangles and Measurement:
Determine if the given triangles are similar using the Angle-Angle Similarity Theorem. If necessary, apply the Interior Angles Theorem to find missing angles before identifying corresponding angles.
The method of Indirect measurement uses the properties of similar triangles and proportionality to calculate distances or the dimensions of objects that are difficult to measure directly. For instance, visualize two flag poles under the sunlight; one 15 feet tall pole casts a 12-foot shadow and the other casts an 8-foot shadow. What is the height of the second flagpole?
LHS⋅15=RHS⋅15
ca⋅b=ca⋅b
Multiply
Calculate quotient
Dylan is a skater who enjoys exploring the math behind the ramps, obstacles, and shadows at a local skate park. One sunny day, he took a break under a tall tree and noticed his shadow next to the tree's shadow. This sparked his curiosity about the tree's height, and he decided to use its shadow to calculate it.
The ratio of the lengths of corresponding sides of similar triangles is always the same.
Substitute values
Add terms
LHS⋅CE=RHS⋅CE
LHS⋅79=RHS⋅79
LHS/13=RHS/13
Dylan is enjoying his time skating at the park. He drops-in on a triangular-shaped ramp. He begins his descent from a height of 15 feet, which is also the height of the ramp. After he glides down the slope for 20 feet, he realizes that he is now only 70% as high as when he started.
The ratio of the lengths of corresponding sides of similar triangles is always the same.
Substitute values
Calculate quotient
LHS⋅(20+BE)=RHS⋅(20+BE)
Distribute 0.7
LHS−0.7BE=RHS−0.7BE
Rearrange equation
LHS/0.3=RHS/0.3
Use a calculator
Later that day, Dylan returned home and realized that he still forgot about his math homework. He needs to finish it so that he can have free time on Saturday to go skateboarding again. His homework requires him to compare a pair of slope triangles that lie on the same line.
Consider that the side of each square in the grid is 1 unit. Help Dylan complete his homework.
LHS⋅BE=RHS⋅BE
LHS⋅DE=RHS⋅DE
LHS/BC=RHS/BC
LHS/DE=RHS/DE
This means that AC=3 and BC=2. Apply a similar reasoning to find the lengths of BE and DE.
riseto the horizontal change or
run. This ratio remains equal across any two slope triangles formed by that line.
At Dylan's skate park, there is a cool shelter that covers the entire skateboard track, providing shade for everyone during their skate sessions. Seeing the roof line, Dylan thinks it is the perfect chance to apply his new school knowledge about slope triangles on the same line.
With the help of a friend, Dylan measured the rise and run at various points on one of the slopes of the roof and sketched a diagram.
Now, he is curious whether the slope of the roof line remains consistent over the different areas. Help Dylan figure out the roof's slope and see if it remains the same everywhere.
Start by choosing two points on the roof line and find the slope using the Slope Formula. Next, verify that the slope is the same by selecting a different set of points.
Substitute (2,4.46) & (0,3.9)
Subtract terms
Calculate quotient
Substitute (6.25,5.65) & (4,5.05)
Subtract terms
Calculate quotient
Little Leapand
Giant Glide.Dylan draws them as triangles that look similar on paper, but
Giant Glideis just a bigger version of
Little Leap.
Little Leapramp?
Giant Glideramp?
Little Leapramp. It is formed by the legs of a triangle measuring 18.75 feet and 11.25 feet, with a hypotenuse of 21.87 feet. Add up the length of all three sides to find the perimeter of the
Little Leapramp.
Giant Glideramp can be found in a similar way. The legs of the triangle are of lengths 75 and 45 feet, respectively, while the hypotenuse has a length of 87.48 feet. Add these lengths to determine the perimeter of the triangle.
Giant Glideramp is 207.48 feet.
Are the pair of triangles similar?
We will use the Angle-Angle Similarity Theorem to determine if the given triangles are similar. Let's first take a look at the given triangles.
We can see that ∠ A and ∠ D are congruent since they both measure 70^(∘). However, ∠ C and angle ∠ E are not congruent. That being said, ∠ B might still be congruent with ∠ E. We can determine the measure of ∠ B by using the Interior Angles Theorem, which states that the sum of all interior angles is 180^(∘). Interior Angles Theorem m∠ A+ m∠ B + m∠ C=180^(∘) Therefore, we can subtract m∠ A and m∠ C from 180^(∘) to find m∠ B. m∠ B=180^(∘)-70^(∘)-39^(∘) ⇓ m∠ B=71^(∘) This means that m∠ B is 71^(∘).
Now that we know m∠ B, we can see that ∠ B and ∠ E are congruent. Since we have two pair of congruent angles, the Angle-Angle Similarity Theorem tells us that the triangles are similar. ∠ A ≅ ∠ D ∠ B ≅ ∠ E ⇓ △ ABC ~ △ DEF
We will use a similar process to determine whether the triangles are similar. Start by examining the given triangles.
We have two angles, ∠ A and ∠ D, that are congruent. Let's see if we can find another pair of congruent angles by determining the measure of ∠ B. To do so, let's subtract m∠ A and m∠ C from 180^(∘). m∠ B=180^(∘) - 63^(∘) -55^(∘) ⇓ m ∠ B = 62^(∘) We can find m∠ F using a similar process. m∠ F=180^(∘) - 55^(∘) -55^(∘) ⇓ m ∠ F = 70^(∘) Therefore, m∠ B is 62^(∘) and m∠ F is 70^(∘).
Now that we know all the angle measures, we can see that there are no two pairs of congruent angles between these triangles. Therefore, we can conclude that the triangles are not similar.
Let's apply a similar fashion to find out if the following triangles are similar.
We can observe that ∠ C and ∠ F are congruent since they have the same measure. Next, we will check if we can identify another pair of congruent angles. To do so, we have to calculate m∠ A by subtracting m∠ B and m∠ C from 180^(∘). m∠ A=180^(∘) - 95^(∘) -47^(∘) ⇓ m ∠ A = 38^(∘) The measure of angle A is 38^(∘).
From the diagram, we can see that ∠ A is congruent to ∠ D. We have now found two pairs of congruent angles between △ ABC and △ DEF. This means that the two triangles are similar. ∠ A ≅ ∠ D ∠ C ≅ ∠ F ⇓ △ ABC ~ △ DEF
Use the similarity between the pair of triangles to find the missing side length.
We are told that △ ABC and △ DEF are similar triangles.
Because of the similarity, the ratio between corresponding sides is equal. In this case, AB corresponds to DE and AC corresponds to DF. We can use this information to write a proportion that relates the side lengths of the two triangles. AB/DE=AC/DF We have been given the values of AB, AC, and DE, so we can substitute these values into the proportion and solve for DF.
This means that DF equals 4.8 feet.
This time, we need to determine the value of EF. Let's begin by considering the given triangles.
Since the triangles are similar, we know that the ratio between corresponding sides is equal. In this case, DE corresponds to AB and EF corresponds to BC. Therefore, we can set up the following proportion. DE/AB=EF/BC We can substitute the values of DE, AB, and BC, and solve the proportion for EF.
Therefore, EF is 6 centimeters.
Take a look at the diagram that shows the shadows cast by a 2-foot tall dog and a tree.
Let's start by looking at the given diagram.
Assuming that the tree and the dog are perpendicular to the ground, they create right angles with the ground. In addition, the angles formed by the rays of the Sun when they hit each object and the ground are equal. This implies that there are two pairs of congruent angles, resulting in two similar triangles as per the Angle-Angle Similarity Theorem.
This means the ratio of the tree's height to the dog's height is equal to the ratio of the tree's shadow to the dog's shadow since the corresponding sides of similar triangles are proportional. Tree's Height/Dog's Height=Tree's Shadow/Dog's Shadow ⇓ h/2=25/5 Let's solve this proportion to find the value of h, which corresponds to the height of the tree.
Therefore, the height of the tree is 10 feet.
Observe the diagram of the shadows cast on the ground at the same spot by a house and a school building.
Let's begin by considering the given diagram.
Let's assume that the house and the school are positioned at right angles to the ground. Also, the angles created by the Sun's rays as they hit each object and the ground are equal. This results in two pairs of congruent angles, which satisfies the Angle-Angle Similarity Theorem and creates two similar triangles.
This means that the ratio of the school's height to the house's height equals the ratio of the school's shadow to the house's shadow. This is because the ratio between corresponding sides of similar triangles are equal. School's Height/House's Height=School's Shadow/House's Shadow ⇓ h/3=12/6 Let's solve this proportion to find the value of h.
Therefore, the height of the school is 6 meters.