Sign In
| 12 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
The concept of set is used in daily life to refer simply to a group of objects. In mathematics, these objects are defined according to some properties. Now, sets will be defined based on some characteristics and the different ways to describe them.
A set is a collection of well-defined unique objects called elements. Sets are often illustrated by a Venn diagram, but there are several other ways to visualize them.
Verbal Description | All negative integers greater than -5. |
---|---|
Roster Notation | {-1,-2,-3,-4} |
Set-Builder Notation | {x ∣ x is a negative integer greater than -5} |
Each way of describing a set will be discussed and a corresponding example will be shown.
the set of delicious dishesis not a valid description because delicious is not well-defined. However,
the set of desserts with chocolateis valid because including chocolate is an objective description.
∣or
:is written. Then, the common characteristics of the elements are defined. Finally, the whole notation is enclosed in curly brackets.
∣and
:are read as
such that.The above example can be read as
the set of all numbers x such that x is an odd integer greater than negative 3.
It is also possible to show a set visually by writing all the elements inside a closed shape. This method is called Venn Diagram.
A Venn diagram is a way of illustrating sets. Here, a rectangle representing the universal set, usually denoted as U
or E,
is drawn. Inside the rectangle circles are typically drawn to represent sets. If the sets have elements in common, circles that represent sets must intersect. In the example, sets A and B are illustrated.
Examine the following Venn Diagram. Determine whether the number belongs to the sets shown or list the elements of the set shown in the roster notation.
If all the elements of a set A are contained in another set B, then A is a subset of B. This relationship can be written as A⊆B.
A Venn diagram visualizes the expression.
As an example, consider the set B={1,2,3}. All of its subsets are shown in the table.
Subset With No Elements | {} or ∅ |
---|---|
Subsets With One Element | {1},{2},{3} |
Subsets With Two Elements | {1,2},{2,3},{1,3} |
Subset With Three Elements | {1,2,3} |
⊂.
A number set is a collection of numbers that allows different types of numbers to be placed in various categories. Listed are some of the most common number sets.
Notice that the elements of some numbers sets are also the elements of another number set. For instance, all natural numbers are also integers. This means that natural numbers are the subset of integers. With these in mind, consider the applet at the beginning of the lesson once again. The relations between the number sets can be shown as the following way.
In the following table, each set will be shown by using the roster notation.
Number Set | Roster Notation |
---|---|
Natural Numbers | {1,2,3,…} |
Whole Numbers | {0,1,2,3,…} |
Integer Numbers | {…,-2,-1,0,1,2,…} |
Rational Numbers | {…,-23,-2,-1,0,1,2,95,…} |
Irrational Numbers | {π,e,2,…} |
Real Numbers | {…,-23,-2,-1,0,1,2,95,π,e,2,…} |
Recall that a number can belong to more than one number set. For instance, 0 is a whole number, but it is an integer, a rational number, and a real number at the same time. Consider the given numbers in the following applet and determine all the number sets that include the number.
Vincenzo is a professional athlete and captain of the an amputee football team in San Francisco — Bayside Flyers. Since he became the team captain, the Flyers have won five different trophies. Vincenzo wants to display the trophies in order of height from shortest to tallest.
Round all the numbers to one decimal place and plot them on a number line.
Approximation | Square of Approximation | Comparison |
---|---|---|
9.1 | 9.1×9.1=82.81 | Approximation is low |
9.2 | 9.2×9.2=84.64 | Approximation is low |
9.3 | 9.3×9.3=86.49 | Approximation is low |
9.4 | 9.4×9.4=88.36 | Approximation is low |
9.5 | 9.5×9.5=90.25 | Approximation is high |
Rewrite π as 3.141592…
Multiply
Round to 1 decimal place(s)
In this lesson, it was mentioned that natural numbers, whole numbers, integers, rational numbers, and irrational numbers are real numbers. Considering that vast range, the set of real numbers must be the biggest number set ever. Right?🤔
Well, there is what is called an imaginary number I. Imaginary numbers combined with real numbers form a set of complex numbers C.
Consider the following verbal descriptions of some sets. Write each set in roster form.
The roster form lists all elements in a set within curly brackets and separates them with commas. We are asked to list all integers greater than -3 and less than 5. These numbers are to the right side of -3 and to the left side of 5 in a number line.
Now that we identified the set, let's list its elements. -2, -1, 0, 1, 2, 3, 4 We can now write the roster form of set A. A={ -2, -1, 0, 1, 2, 3, 4 } Although we can write the elements of a set in any order, writing them in ascending order is a good practice. We just need to be careful to write each once.
We now need to find the whole numbers that are less than 10. Recall that whole numbers start from 0 and increase by one unit indefinitely. The whole numbers less than 10 are to the right side of 0 included and to the left side of 10 in a number line.
Now that we identified the numbers in the set, let's write them down. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 Finally, let's enclose them within curly brackets and add its name. Remember that the order of the elements can be disregarded. B={ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 }
Consider the following sets which are given in roster notation. Choose the best option that represents each set in set-builder notation.
Consider the given set. C={ 2, 3, 5, 7, 11, 13, 17, 19} This set contains odd and even numbers starting from 2 and continuing up to 19. Yet, we need a more specific property to describe these numbers. After going deeper, we can see that these numbers are the first prime numbers up to 19 because the only factors of each are 1 and the numbers themselves.
C contains the first prime numbers less than or equal to 19
We can now use this statement and a variable to represent the elements of set C. In this case, let's use the variable x. We can then say that x is a prime number such that x is less than or equal to 19. Let's write the set-builder notation of C. C={ x | x is a prime number, x ≤ 19 }
Let's look at the given set.
D={ ... , -4, -2, 2, 4, ... }
The numbers in this set are integers. These numbers are also even numbers and the set does not contain 0. This means that D contains even integers different than 0.
D contains even integers different than 0.
Let's now use this statement and the variable x to write the set-builder notation. In this case, x is an even integer different than 0. D={ x | x is an even integer , x ≠ 0 }
We want to identify the common elements between sets A and B. We are given set A in set-builder notation. Let's first write set A into its listing form. A={x | xis an even whole number less than9} ⇕ A={0, 2, 4, 6, 8} A common element is an element that is in both sets. In other words, it is an element that belongs to A and B at the same time. Let's identify these common elements. A&={0, 2, 4, 6, 8} B&={ 4, 5, 6, 7, 8} The common elements are 4, 6, and 8. { 4, 6, 8}
This time we will write all the elements that belong to sets A and B. Recall that each element in a set is unique, so if any element exists in both sets, we will write them once.
A&={0, 2, 4, 6, 8}
B&={ 4, 5, 6, 7, 8}
Great! Let's now write all elements that are in both sets.
{0, 2, 4, 5, 6, 7, 8}
Consider the following Venn Diagram.
We are asked to list the elements of set A. Let's only consider the elements inside the red circle representing set A.
Let's keep in mind that the elements in the overlapping section of A and B are also part of A. We can now list the elements of A. A={-12,7,-8,-5,15,-23,54} Recall that the order is not important while listing the elements of a set.
This time we will list only the elements that are common in the sets A and B. Let's now examine only the overlapping region.
We can see from the diagram that only two elements belong to both sets. {54, -23 }
Finally, we will find the total number of elements in the universal set U. We will list all the elements that we see inside the bigger rectangle.
Note that we should also consider the elements that do not belong to sets A and B but are still inside set U. U={& -12,7,-8, -5,15,54,-23,-13,10, & 67, 98,9,-21,-43,-2,25,0,6,17} There are a total of nineteen elements in the universal set.
Set B includes the letters in the word LETTER. Consider the subsets of set B.
At first, we will list the elements of the given set B. Recall that the elements of a set should be written only once which means we will disregard the duplicates of the letters E and T for this case. L-E-T-T-E-R ⇓ B={ L,E,T,R } Set B has four elements. Recall that all elements in a subset are also elements of the original set. Now, we will list all the subsets starting with the ones having zero element, followed by one, two, three, and four elements at most since we have maximum of four elements for this case.
The only subset with zero elements of any set is the empty set. We can write this using the empty set notation. ∅ or { }
There are four elements in our original set. We can use each of these to form the single element subsets. {L}, {E}, {T}, {R}
Next, we will write the subsets including only two-elements. { L, E }, { L, T }, { L, R }, {E, T }, {E, R }, {T, R}
After that, we will write all the three-element subsets. {L, E, T }, {L, E, R }, {L, T, R }, {E, T, R }
The original set has four elements, so we can only form one subset having four elements: the original set itself. { L, E, T, R }
Let's see all these subsets in a table.
Subsets Including n Elements | |
---|---|
n=0 | { } |
n=1 | {L}, {E}, {T}, {R} |
n=2 | { L, E }, { L, T }, { L, R }, {E, T }, {E, R }, {T, R} |
n=3 | {L, E, T }, {L, E, R }, {L, T, R }, {E, T, R } |
n=4 | { L, E, T, R } |
Now, we will consider the given options and see whether they match with the obtained subsets. l { } & ✓ {E,T} & ✓ {T,R } & ✓ {E,B} & * {E,E,T} & * {L,T,R} & ✓ {L,E,T,R} & ✓ {L,E,T,T,E,R} & * Notice that the given set B does not include the letter B. Therefore, it does not include the subset {E,B}. Also, since the elements in the sets {E,E,T} and {L,E,T,T,E,R} are not written only once, they do not even represent a set itself.
Let's consider the table we created in Part A of the subsets of B.
Subsets | Number of Subsets | |
---|---|---|
n=0 | { } | 1 |
n=1 | {L}, {E}, {T}, {R} | 4 |
n=2 | { L, E }, { L, T }, { L, R }, {E, T }, {E, R }, {T, R} | 6 |
n=3 | {L, E, T }, {L, E, R }, {L, T, R }, {E, T, R } | 4 |
n=4 | { L, E, T, R } | 1 |
Let's add all the number of subsets. 1+4+6+4+1=16 Set B has a total of 16 subsets. This applies to any set with four elements. A shortcut for calculating the number of subsets of a set with n elements is with the formula 2^n. In this case, n is 4. 2^4=16
We will determine which of the given numbers are irrational. Let's recall the definition of irrational numbers.
An irrational number is a number that is not rational. So, an irrational number cannot be written as ab where a and b are integers and b≠0.
According to this definition, - 109 is a rational number because it is a fraction. -10/9= -10/9 → Rational Notice that 0 is also a rational number since it can be written as a fraction by choosing a nonzero integer for the denominator. For instance, 03=0. 0= 0/3 → Rational Next, let's recall the fact that the decimal form of an irrational number neither terminates nor repeats. In other words, if a decimal number terminates or repeats then it is rational. This means that both 5.70 and 0.13 are rational. 5.70 → Rational 0.13 → Rational We will now have a look at π. It is also one of the famous irrational number because its expanded form never terminates. π =3.14159265359... → Irrational Note that the cube root of any integer that is not a perfect cube is irrational. This information helps us examine sqrt(71). Notice that 71 is not a perfect cube which makes sqrt(71) an irrational number. sqrt(71) → Irrational Last, we will examine -sqrt(16). Recall that the square root of any whole number is rational if the radicand is a perfect square. Since 16 is a perfect square, we can calculate this root.
This means that -sqrt(16) is rational. Let's see the types of the given numbers as rational or irrational. - 109 &→ Rational 0 &→ Rational 5.70 &→ Rational 0.13 &→ Rational π &→ Irrational sqrt(71) &→ Irrational -sqrt(16) &→ Rational