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Construct your proof based on the Inscribed Angle Theorem.
See solution.
We are asked to prove that two arcs of a circle included between parallel chords are congruent.
Our first step will be constructing AD. Draw AD We have two parallel segments intersected by a transversal.
As we can see, ∠ BAD and ∠ ADC are alternate interior angles. ∠ BAD and ∠ ADC are alternate interior angles. By the Alternate Interior Angles Theorem we know that the alternate interior angles are congruent. ∠ BAD ≅ ∠ ADC By the definition of congruent angles, ∠ BAD and ∠ ADC have the same angle measure. m∠ BAD ≅ m∠ ADC In the first part of our proof we showed that m∠ BAD ≅ m∠ ADC. Next, we will consider the Inscribed Angle Theorem.
By this theorem, we can conclude that m∠ BAD is half mBD and m∠ ADC is half AC. m∠ BAD=1/2mBD m∠ ADC=1/2 mAC Now, since m∠ BAD=m∠ ADC, we can substitute m∠ BAD for m∠ ADC in m∠ ADC= 12mAC. m∠ BAD=1/2mBD m∠ BAD=1/2 mAC Then, we can use the Transitive Property of Equality. 1/2 mAC =1/2mBD By the Multiplication Property of Equality, we can multiply both sides of the above equation by 2 to eliminate the denominators. mAC = mBD Finally, remember that congruent arcs have the same arc measure.
Therefore, the arcs of a circle that are included between parallel chords are congruent. AC ≅ BD