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Inscribed Angle Theorem |
The measure of an inscribed angle is half the measure of its intercepted arc. |
From the theorem, we know the following. m∠ A=1/2m BC Multiplying both sides of the equation by 2, we get that the measure of the arc is twice greater that the measure of ∠ A. 2m∠ A=m BC Let's substitute m∠ A with 48^(∘) and calculate m BC. m BC=2m∠ A=2( 48^(∘))=96^(∘)
Inscribed Angle Theorem |
The measure of an inscribed angle is half the measure of its intercepted arc. |
According to the theorem, the measure of ∠ B is half the measure of the intercepted arc AC. m∠ B=1/2mAC Let's substitute mAC with 110^(∘) and calculate m∠ B. m∠ B=1/2( 110^(∘))=55^(∘)
m∠ A= 48^(∘), m∠ B= 55^(∘)
Add terms
LHS-103^(∘)=RHS-103^(∘)
m∠ C= 77^(∘)
LHS * 2=RHS* 2
Rearrange equation