Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Inscribed Angles
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Exercise 25 Page 785

Start with calculating the value of b using the Inscribed Angle Theorem.

a=30, b=60, c=62, d=124, e=60

Practice makes perfect

We are asked to find the values of the variables on the diagram. Let's calculate them one at a time, starting with b.

Variable b

Consider the following diagram.

As we can see, angle ∠ b intercepts the arc GF, which measures 120^(∘). Let's recall what the Inscribed Angle Theorem states.

Inscribed Angle Theorem

The measure of an inscribed angle is half the measure of its intercepted arc.

By the theorem, the measure of ∠ b is half the measure of GF. Hence, dividing 120 by 2, we can calculate m∠ b. m∠ b=120/2=60^(∘) This way we got that the value of b is 60.

Variable a

Now, we can calculate the value of a. Note that an inscribed angle (a+b)^(∘), which we can call ∠ FHE, is inscribed in a semicircle.

We can apply Corollary 2, which states the following.

Corollary 2

An angle inscribed in a semicircle is a right angle.

It allows us to conclude that ∠ FHE is a right angle. Thus, the sum of a and b is 90^(∘). a+b=90 We already know that b= 60. Let's substitute this value into the equation and calculate a. a+ 60=90 ⇒ a=30

Variable e

Now that we know the value of a, we can find e. From the diagram, we can see that e^(∘) is the measure of an arc intercepted by angle of the measure a^(∘).

By the Inscribed Angle Theorem, the measure of ∠ a is half the measure of GE, which means that arc GE measures twice as much as ∠ a. m∠ a=1/2mGE ⇒ mGE=2m∠ a Let's substitute a with 30 and calculate mGE. mGE=2(30)=60^(∘) We conclude that the value of e is 60.

Variable d

In order to find the value of d, let's use the fact that the measures of arcs around a circle is 360^(∘). This allows us to write the following equation. 56^(∘)+e^(∘)+120^(∘)+d^(∘)=360^(∘) Earlier we have found that e equals 60. Let's substitute this value and solve the equation for d.
56^(∘)+e^(∘)+120^(∘)+d^(∘)=360^(∘)
56^(∘)+ 60^(∘)+120^(∘)+d^(∘)=360^(∘)
234^(∘)+d^(∘)=360^(∘)
d^(∘)=124^(∘)
Therefore, d is equal to 124.

Variable c

Finally, we can calculate the value of c. We can start with analyzing the diagram.

Angle ∠ c is formed by the tangent and chord FH. Let's use Theorem 12-12, which states the following.

Theorem 12-12

The measure of an angle formed by a tangent and a chord is half the measure of the intercepted arc.

From the diagram we can see that angle ∠ c intercepts arc FG. Therefore by the theorem its measure is half the measure of FG. m∠ c=1/2mFG The measure of arc FG is d^(∘), which we have found to be 124^(∘). Let's substitute this value into the equation and calculate m∠ c. m∠ c=1/2( 124^(∘))=62^(∘) Therefore, the value of c is 62.