Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Cumulative Standards Review

Exercise 17 Page 758

Notice that you can evaluate the height of an isosceles trapezoid using the Pythagorean Theorem.

72 square units

Practice makes perfect

Let's take a look at the given diagram. Notice that in an isosceles trapezoid the legs l are congruent.

Since we are given that the perimeter of the figure is 44 units, we can write and solve equation for l. 20+ l+ l+ 4= 44 Let's solve the above equation.
20+l+l+4=44
24+2l=44
2l=20
l=10
The leg length is 10 units. Next let's draw the heights h of the trapezoid. Notice that these heights divide the trapezoid into two congruent right triangles and a rectangle.

Next, if we call the length of the second leg of each triangle x, then we can see that two times x plus 4 is equal to 20. 2 x+ 4= 20 ⇒ x=8 Let's add this information to our diagram.

Now notice that we can evaluate h using the Pythagorean Theorem. According to this theorem, the sum of the squared legs of a right triangle is equal to its squared hypotenuse.
h^2+ 8^2= 10^2
h^2+64=100
h^2=36
h=6
Notice that since h represents the height, we considered only positive cases when taking a square root of h^2.
Now we have all the information we need to evaluate the area of the trapezoid. Let's recall the formula for this area. A=1/2h(b_1+b_2) Finally, let's substitute the height and both bases of our triangle into the above formula.
A=1/2h(b_1+b_2)
A=1/2( 6)( 20+ 4)
A=1/2(6)(24)
A=1/2(144)
A=144/2
A=72
The area of the trapezoid is 72 square units.