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Notice that the arc measure between two consecutive hours on the clock is 30^(∘).
Diagram:
The Distance Between Pilot A and the Object: ≈ 462 ft
We are asked to draw a diagram showing the possible locations of the two planes and the object given the references to the dial of a clock. Then we will use our diagram to find the distance between Pilot A and the object. Let's start with the first part!
We are asked to suppose that two pilots flying in the same direction spot the same object. First, we know that Pilot A reports the object at 12 o'clock.
Next, we are given that Pilot B reports the object at 2 o'clock and at the same time Pilot A reports seeing the other airplane at 9 o'clock.
Notice that the arc measure between two consecutive hours on the clock is 30^(∘). This means that the locations form a 30^(∘)-60^(∘)-90^(∘) triangle.
Now we are given that the planes are 800 feet apart and we want to evaluate the distance between Pilot A and the object. Let d represent this distance.
Recall that in a 30^(∘)-60^(∘)-90^(∘) triangle the length of the longer leg is sqrt(3) times the length of the shorter leg. Using this information, we can write an equation. 800= dsqrt(3) ⇓ d=800/sqrt(3)≈ 462 Pilot A is approximately 462 feet from the object.