Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
5. Trigonometry and Area
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Exercise 6 Page 646

Start by finding the perimeter. Then, find the apothem. Finally, substitute the values of the perimeter and the apothem into the formula A= 12 to find the area of the polygon.

173.8cm^2

Practice makes perfect

We want to find the area of a octagon with a side length of 6cm. To do so we will start by finding its perimeter. Then, we will use a right triangle to find the apothem. Finally, we will use the formula A= 12ap to find the area of the polygon.

Perimeter

Let's start by drawing our octagon.

Recall that in a octagon, all 8 sides are congruent, and we are told that the side length is 6cm. Therefore, we can find the perimeter by multiplying 6 by 8. Perimeter: 6 * 8= 48cm

Therefore, the perimeter is 48cm.

Measure of the Angles Formed by Two Radii

Now let's draw the radii of the polygon. Since all of the radii are congruent, they form 8 congruent isosceles triangles. Moreover, since corresponding angles of congruent figures are congruent, all the vertex angles of the isosceles triangles formed by the radii are congruent.

Recall that a full turn of a circle measures 360^(∘). Therefore, we can find the measure of the central angles by dividing 360 by the number of angles. Central Angle Measure: 360/8= 45^(∘) The measure of the vertex angle of each of the isosceles triangles formed by the radii is 45^(∘).

Apothem

Let's consider one of the isosceles triangles formed by two radii and a side of the polygon.

The apothem bisects both the angle whose measure is 45^(∘) and the side whose length is 6cm. Therefore, the apothem divides the isosceles triangle into two right triangles with an acute angle of measure 452= 22.5^(∘) and opposite side length 62= 3cm. Let's look at just one of these right triangles.

In the above right triangle we know the measure of an angle and the length of its opposite side, so we can use the tangent ratio to find the length of its adjacent side.
tan θ = Length of opposite side toθ/Length of adjacent side toθ
tan 22.5^(∘)=3/a
Solve for a
tan 22.5^(∘) * a=3
a=3/tan 22.5^(∘)
a=7.242640...
a ≈ 7.2
We found that the apothem of the regular polygon is approximately 7.2cm.

Area of the Regular Polygon

The area of a regular polygon is half the product of the apothem and the perimeter. Since we already know that the apothem is approximately 7.2cm and the perimeter is 48cm, we can substitute these values in the formula A= 12ap to find the area.
A=1/2ap

a ≈ 7.2,p= 48

A≈ 1/2( 7.2)( 48)
Evaluate right-hand side
A≈ 1/2(347.646753)
A≈ 347.646753/2
A≈ 173.823376...
A≈ 173.8
The area of the regular polygon to the nearest tenth is 173.8cm^2.