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| 10 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Izabella has a triangular table in her kitchen. She wants to cover the surface of the table with a tablecloth. Two side lengths and two angle measures of the table are given.
Typically to find the area of a triangle, the measurements of its height and base are used. On the other hand, if the lengths of two sides and the measure of their included angle are known, what should be the process to find the area of the triangle?
In △ABC, the lengths of AB and BC are 6 and 8 inches, respectively. The measure of ∠ABC varies from 15∘ to 90∘.One way of finding the area of an equilateral triangle is by using trigonometric ratios.
Izabella wants to finish her math homework before she goes out to buy some fabric for her table. She is given an equilateral triangle whose side length is 1 unit.
Izabella's homework problem is to find the area of this triangle. Help her find the answer.
What information is needed to find the area of a triangle?
The area of a triangle is half the product of its base and the corresponding height. Therefore, the height of △ABC needs to be found. Suppose line ℓ bisects ∠A and intersects AB at point M.
Since △ABC is an equilateral triangle, the measure of each of its interior angles is 60∘. Consequently, ∠ACM measures 30∘.
Considering △ACM, it can be concluded that ∠AMC is a right angle by the Triangle Angle Sum Theorem.
In the previous example, it was shown that trigonometric ratios can be used to find the area of a triangle given the lengths of two sides and the measure of their included acute angle. What happens if the included angle is obtuse?
In △ABC, the lengths of AB and BC are 6 and 8 inches, respectively. The measure of ∠ABC varies from 15∘ to 165∘.Izabella finished her homework and is ready to go. On her way out, she notices an empty triangular region in the garden.
Her father wants to fill this region with topsoil. To figure out how much topsoil he needs, he asks Izabella to find the area of the region. Help them find the area. If it is necessary, round the answer to the nearest square foot.
Begin by drawing the external altitude of the 40-foot side.
Begin by drawing the external altitude of the 40-foot side.
b=40, h=2.598076…
b1⋅a=ba
Calculate quotient
Use a calculator
Round to nearest integer
There is another way of finding the area of a triangle that can be derived from the previous examples.
To find the first formula, start by drawing the altitude from B and let h be its length. Since the altitude is perpendicular to the base, it generates two right triangles.
To deduce the third formula, the altitude from C or A should be drawn. In this case, the altitude from C will be arbitrarily drawn and labeled D with a length of h. Because ∠B is obtuse, the altitude will lie outside the triangle.
While sitting on the bus on the way to the fabric store, Izabella began daydreaming about a formula for the area of a triangle involving the sine ratio. She dreams about applying this formula to find the area of the Bermuda Triangle which she remembers from the movie Gulliver's Travels.
Given the lengths of two sides and the measure of their included angle, calculate the area of the Bermuda Triangle. Round the answer to the nearest square mile.
Use the formula for the area of a triangle involving the sine ratio.
Substitute values
Multiply
b1⋅a=ba
Calculate quotient
Use a calculator
Round to nearest integer
In the following triangles, the lengths of two sides and the measure of their included angle is given. By using the formula derived earlier, find the area of the triangles. Round the answer to one decimal place.
By using a formula derived in this lesson, the challenge presented at the beginning can be solved. Recall that the question asked what amount of fabric Izabella needs to cover the triangular table.
Begin by finding the included angle. Then use the formula for the area of a triangle using the sine ratio.
To find how much fabric Izabella needs, the surface area of the table must be found. Therefore, begin by finding the included angle.
Multiply
b1⋅a=ba
Calculate quotient
Use a calculator
Round to 1 decimal place(s)
Determine the sides labeled x and y in the triangle if you know that y is 5 centimeters longer than x and that the area is 6 square centimeters.
We know that y is 5 units longer than x. Therefore, we can rewrite y as x+5.
The included angle to the two sides has a measure of 30^(∘). By substituting the angle and the two sides into the formula for calculating a triangle's area using sine, we can create a quadratic equation that contains x.
We can solve this equation by completing the square.
We know that x is 3 centimeters. Then y, which is 5 centimeters longer than x, is 8 centimeters.
Does the triangle for any measure of ∠v have an area of 12 square centimeters? Please explain your reasoning.
Let's substitute the given sides and the area we want the triangle to have in the formula for calculating the area of a triangle using sine and try to solve for v.
To calculate the inverse sine of 2 on your graphing calculator, press 2ND, and SIN and then 2. If we try to calculate this value, we notice that we get an error.
The equation sin v=2 can not be solved. This is because the sine value of an acute angle in a right triangle must be less than 1. To understand why, let us have a look at the definition of sine. sin θ =Opposite/Hypotenuse The hypotenuse in a right triangle is always greater than the legs. This means that the sine ratio must be less than 1. Therefore, we can conclude that we cannot have a triangle with sides of 3 and 4 centimeters with an area of 12 square centimeters. That is regardless of the included angle ∠ v at any measure.
The triangle has an area of 3 square units.
While sitting in the bus, Kevin wants to determine the measure of ∠v. He makes the following calculation on a piece of paper.
If we calculate the inverse sine of 0.5769, we get an angle with a measure of approximately 35^(∘).
However, remember that the sine value is defined as the y-coordinate on the unit circle. There is more than one angle that corresponds to a y-value of 0.5769. Let's view this situation in the unit circle.
Both 35^(∘) and its supplementary angle of 145^(∘) have a sine value of 0.5769. Therefore, the angle Kevin is looking for is 145^(∘), not 35^(∘).
Notice that a graphing calculator always answers with the acute angle of given sine value. If this is not the correct angle, we must calculate the correct one by subtracting the result from 180^(∘).