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| 10 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Izabella has a triangular table in her kitchen. She wants to cover the surface of the table with a tablecloth. Two side lengths and two angle measures of the table are given.
Typically to find the area of a triangle, the measurements of its height and base are used. On the other hand, if the lengths of two sides and the measure of their included angle are known, what should be the process to find the area of the triangle?
In △ABC, the lengths of AB and BC are 6 and 8 inches, respectively. The measure of ∠ABC varies from 15∘ to 90∘.One way of finding the area of an equilateral triangle is by using trigonometric ratios.
Izabella wants to finish her math homework before she goes out to buy some fabric for her table. She is given an equilateral triangle whose side length is 1 unit.
Izabella's homework problem is to find the area of this triangle. Help her find the answer.
What information is needed to find the area of a triangle?
The area of a triangle is half the product of its base and the corresponding height. Therefore, the height of △ABC needs to be found. Suppose line ℓ bisects ∠A and intersects AB at point M.
Since △ABC is an equilateral triangle, the measure of each of its interior angles is 60∘. Consequently, ∠ACM measures 30∘.
Considering △ACM, it can be concluded that ∠AMC is a right angle by the Triangle Angle Sum Theorem.
In the previous example, it was shown that trigonometric ratios can be used to find the area of a triangle given the lengths of two sides and the measure of their included acute angle. What happens if the included angle is obtuse?
In △ABC, the lengths of AB and BC are 6 and 8 inches, respectively. The measure of ∠ABC varies from 15∘ to 165∘.Izabella finished her homework and is ready to go. On her way out, she notices an empty triangular region in the garden.
Her father wants to fill this region with topsoil. To figure out how much topsoil he needs, he asks Izabella to find the area of the region. Help them find the area. If it is necessary, round the answer to the nearest square foot.
Begin by drawing the external altitude of the 40-foot side.
Begin by drawing the external altitude of the 40-foot side.
b=40, h=2.598076…
b1⋅a=ba
Calculate quotient
Use a calculator
Round to nearest integer
There is another way of finding the area of a triangle that can be derived from the previous examples.
To find the first formula, start by drawing the altitude from B and let h be its length. Since the altitude is perpendicular to the base, it generates two right triangles.
To deduce the third formula, the altitude from C or A should be drawn. In this case, the altitude from C will be arbitrarily drawn and labeled D with a length of h. Because ∠B is obtuse, the altitude will lie outside the triangle.
While sitting on the bus on the way to the fabric store, Izabella began daydreaming about a formula for the area of a triangle involving the sine ratio. She dreams about applying this formula to find the area of the Bermuda Triangle which she remembers from the movie Gulliver's Travels.
Given the lengths of two sides and the measure of their included angle, calculate the area of the Bermuda Triangle. Round the answer to the nearest square mile.
Use the formula for the area of a triangle involving the sine ratio.
Substitute values
Multiply
b1⋅a=ba
Calculate quotient
Use a calculator
Round to nearest integer
In the following triangles, the lengths of two sides and the measure of their included angle is given. By using the formula derived earlier, find the area of the triangles. Round the answer to one decimal place.
By using a formula derived in this lesson, the challenge presented at the beginning can be solved. Recall that the question asked what amount of fabric Izabella needs to cover the triangular table.
Begin by finding the included angle. Then use the formula for the area of a triangle using the sine ratio.
To find how much fabric Izabella needs, the surface area of the table must be found. Therefore, begin by finding the included angle.
Multiply
b1⋅a=ba
Calculate quotient
Use a calculator
Round to 1 decimal place(s)
Determine the area of the triangle in centimeters. Round the answer to one decimal place.
Examining the diagram, we see that we know two sides and their included angle. Let's recall the formula of Area of a Triangle Using Sine. A=1/2absin C This formula allows for us to calculate the area of a triangle if we know the length of two sides a and b and the included angle C.
For this triangle, we also know two sides and one angle. Therefore, we can use the formula Area of a Triangle Using Sine, once again, to determine the area.
As in Part A and B, we have the necessary information to determine the triangle's area using sine.
Determine the area of the triangle in centimeters. Round the answer to one decimal place.
In the given triangle, we know two angles. To be able to use the formula for calculating the triangle's area, we need to determine the remaining angle by using the Interior Angles Theorem. m∠ C + 38^(∘) +57^(∘) = 180^(∘) ⇓ m∠ C =85^(∘) Now that we know two sides and their included angle, we can determine the area of the triangle.
The area of the triangle is about 9.7 square centimeters.
Notice that we have been given the exterior angle of one of the angles in the triangle. Since these two angles form a linear pair, we can determine the inner angle by equating these angles with 180^(∘) and solving the resulting equation. m∠ C + 136^(∘) = 180^(∘) ⇓ m∠ C =44^(∘) Now we can calculate the area.
The triangle has an area of about 6.3 square centimeters.
In the following diagrams, the areas and leg lengths are given in centimeters. Determine the measure of the acute angle v of the triangle. Round the answer to the nearest whole number of degrees.
By substituting the sides and the given area into the formula for calculating the Area of a Triangle Using Sine, we can solve for the included angle.
As we can see, the measure of the acute ∠ v is about 68^(∘).
We will solve for ∠ v in the same way as we did in Part A.
In this triangle, the measure of the acute angle labeled v is about 20^(∘).
An equilateral triangle is also equiangular. This means that it has three congruent angles, each with a measure of 60^(∘). Let's draw the triangle.
Let's determine the triangle's area by using the formula for the Area of a Triangle Using Sine.
The area of the triangle is about 15.6 square centimeters.
What is the area of the quadrilateral in centimeters? Round the answer to one decimal place.
To determine the area of the quadrilateral, we will divide it into two triangles and label them A_1 and A_2.
Notice that we now have two triangles where we know two sides and their included angle. This means we can calculate the area of the triangles using sine. Let's substitute each set of information into the formula for calculating the area. A_1&=1/2(4.2)(4.1)(sin 59^(∘)) [0.9em] A_2&=1/2(2.8)(2.2)(sin 108^(∘)) The sum of these equals the area of the quadrilateral, which we will label A_Q.
The quadrilateral's area is about 10.3 square centimeters.