Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
5. Trigonometry and Area
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Exercise 37 Page 647

Use tangent ratio to find the apothem of each pentagon.

About 48.2 cm^2

Practice makes perfect
We want to find the areas of the pentagons. To do so, we first need to find their apothems. We know that an apothem bisects the central angle and the side opposite to the angle. The formula for the measure of the central angle of a regular polygon is 360n, where n is the number of sides in the polygon. Let's find the central angle of a pentagon. 360/n ⇔ 360/5=72 The measure of the central angle of a regular pentagon is 72^(∘). Since the apothem bisects this angle, the measure of the angle between the apothem and the radius of the pentagon is 36^(∘). Let's show the apothem of each pentagon.

Using the tangent ratio, we can find the apothems, a and b.

Tangent Ratio Rewrite
Pentagon 1 tan 36^(∘)=3/a a= 3/tan36 ^(∘)
Pentagon 2 tan 36^(∘)=4/b b= 4/tan36 ^(∘)
Next, we will find the perimeters of the pentagons. ccc & Pentagon1 & Pentagon2 [0.5em] Perimeter: & 5* 6 = 30 & 5* 8 = 40 We can now use the area formula for a regular polygon, A= 12ap. We can find the area A_1 of Pentagon 1 by substituting 3tan36^(∘) for a and 30 for p.
A_1=1/2ap
A_1=1/2 * 3/tan36^(∘) * 30
Evaluate right-hand side
A_1=90/2tan36^(∘)
A_1=45/tan36^(∘)
A_1=61.937186 ...
A_1≈ 61.9
The area of Pentagon 1 is about 61.9 cm^2. We can find the area A_2 of Pentagon 2 the same way.
A_2=1/2bp
A_2=1/2 * 4/tan36^(∘) * 40
Evaluate right-hand side
A_2=160/2tan36^(∘)
A_2=80/tan36^(∘)
A_2=110.110553 ...
A_2≈ 110.1
Finally, to find the area A_p of the shaded region, we will subtract A_1 from A_2.
A_p=A_2-A_1
A_p= 110.1- 61.9
A_p=48.2
Therefore, the area A_p of the shaded region is about 48.2 cm^2.