5. Working With Sets
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To solve the inequality, isolate x.
{ x | xis a real number }
To solve the inequality, we have to isolate x. By distributing - 3 on the left-hand side and using inverse operations, we can isolate the variable.
Distribute - 3
Add terms
LHS+23≥RHS+23
LHS+12x≥RHS+12x
The statement 0≥ 0 is always true. A number will always be equal to itself. Therefore, all real numbers are solutions to this equation. Now we can use the result to form a solution set in set-builder notation. { x | x is a real number}