body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Dashboard

PA

Pearson Algebra 1 Common Core, 2011 View details

5. Working With Sets

Finish the assignment

Continue to next subchapter

Exercise 17 Page 197

Start by solving the inequality.

{ p | p≥ 1}

Practice makes perfect

Before we can write the inequality in set-builder notation, we have to solve the inequality by isolating p.

2(3p-11)≥- 16

DivIneq

.LHS /2.≥.RHS /2.

3p-11≥- 8

AddIneq

LHS+11≥RHS+11

3p≥ 3

DivIneq

.LHS /3.≥.RHS /3.

p≥ 1

To use set-builder notation, we need a variable, which in this case is p, and a statement describing the elements of the set. Knowing that p≥ 1 is the solution to the inequality, we can write the solution in set-builder notation. { p | p≥ 1} This can be read as the set includes any value of p such that p is greater than or equal to 1.