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Pearson Algebra 1 Common Core, 2011 View details

5. Working With Sets

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Exercise 18 Page 197

Start by solving the inequality.

{ k | k<- 13}

Practice makes perfect

Before we can write the inequality in set-builder notation, we have to solve the inequality by isolating k.

3(2k+12)<- 42

DivIneq

.LHS /3.<.RHS /3.

2k+12<- 14

SubIneq

LHS-12

2k<- 26

DivIneq

.LHS /2.<.RHS /2.

k<- 13

To use set-builder notation, we need a variable, which in this case is k, and a statement describing the elements of the set. Knowing that k<- 13 is the solution to the inequality, we can write the solution in set-builder notation. { k | k<- 13} This can be read as the set includes any value of k such that k is less than - 13.