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PA

Pearson Algebra 1 Common Core, 2011 View details

5. Working With Sets

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Exercise 54 Page 199

Start by solving the inequality.

F

Practice makes perfect

First we have to solve the inequality by isolating x.

- 9x+17≥- 64

SubIneq

LHS-17≥RHS-17

- 9x≥- 81

DivNegIneq

Divide by - 9 and flip inequality sign

x≤ 9

Knowing that x≤ 9 is the solution to the inequality, we can write the solution in set-builder notation. { x | x≤ 9} This can be read as "the set includes any value of x such that x is less than or equal to 9." This corresponds to answer F.