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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
5. Working With Sets
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Exercise 55 Page 199

Since the triangles are similar, the ratio between corresponding sides is the same.

D

Practice makes perfect

Since the given triangles are similar, the ratio between corresponding sides is the same. We can write this as the following proportion. 7/5=FG/9 By solving for FG, we determine the missing length.

7/5=FG/9
MultEqn

LHS * 9=RHS* 9

7/5* 9=FG
MoveRightFacToNum

a/c* b = a* b/c

63/5=FG
â–¼
Write fraction as a mixed number
Rewrite

Rewrite 63 as 60+3

60+3/5=FG
WriteSumFrac

Write as a sum of fractions

60/5+3/5=FG
CalcQuot

Calculate quotient

12+3/5=FG
AddTerms

Add terms

12 35=FG
RearrangeEqn

Rearrange equation

FG=12 35

The missing length is 12 35. This corresponds to option D.

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arrow_right Lesson Check p.197
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arrow_right Practice and Problem-Solving Exercises p.197-199
Practice and Problem-Solving Exercises 9 (Page 197)
Practice and Problem-Solving Exercises 10 (Page 197)
Practice and Problem-Solving Exercises 11 (Page 197)
Practice and Problem-Solving Exercises 12 (Page 197)
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Practice and Problem-Solving Exercises 35 (Page 198)
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Practice and Problem-Solving Exercises 40 (Page 198)
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arrow_right Standardized Test Prep p.199
Standardized Test Prep 53 (Page 199)
Standardized Test Prep 54 (Page 199)
Standardized Test Prep 55 (Page 199)
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arrow_right Mixed Review p.199
Mixed Review 58 (Page 199)
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