body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

6. Trigonometric Ratios

Continue to next subchapter

Exercise 50 Page 651

To simplify the given expression, all radicals need to have like radicands.

B

Practice makes perfect

Radicals can only be added or subtracted when they have like radicands. a sqrt(x) + b sqrt(x) = (a+b) sqrt(x) asqrt(x)-bsqrt(x)=(a-b)sqrt(x)Let's use perfect squares to simplify our radicals to see if we can create like terms.

3sqrt(12) + 2sqrt(3)

SplitIntoFactors

Split into factors

3sqrt(4* 3) + 2sqrt(3)

sqrt(a* b)=sqrt(a)*sqrt(b)

3* sqrt(4)* sqrt(3)+2sqrt(3)

Calculate root

3* 2* sqrt(3)+2sqrt(3)

Multiply

6sqrt(3)+2sqrt(3)

Now we will use the Distributive Property to perform the addition.

6sqrt(3)+2sqrt(3)

Factor out sqrt(3)

(6+2)sqrt(3)

Add terms

8sqrt(3)

This result corresponds to option B.

Subchapter links

Lesson Check p.649

Practice and Problem-Solving Exercises p.649-651

Standardized Test Prep p.651

Mixed Review p.651