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(x+2)(x+4)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
x^2+6x+8
In this case, we have 8. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)
| Factor Constants | Product of Constants |
|---|---|
| 1 and 8 | 8 |
| -1 and -8 | 8 |
| 2 and 4 | 8 |
| -2 and -4 | 8 |
Next, let's consider the coefficient of the linear term. x^2+6x+8 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 6.
| Factors | Sum of Factors |
|---|---|
| 1 and 8 | 9 |
| -1 and -8 | - 9 |
| 2 and 4 | 6 |
| -2 and -4 | - 6 |
We found the factors whose product is 8 and whose sum is 6. x^2+6x+8 ⇔ (x+2)(x+4)
Distribute (x+4)
Distribute x
Distribute 2
Subtract term
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!