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(x+3)(x+6)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
x^2+9x+18
In this case, we have 18. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same signs - both positive or both negative.
| Factor Constants | Product of Constants |
|---|---|
| 1 and 18 | 18 |
| -1 and -18 | 18 |
| 2 and 9 | 18 |
| -2 and - 9 | 18 |
| 3 and 6 | 18 |
| -3 and - 6 | 18 |
Next, let's consider the coefficient of the linear term. x^2+9x+18 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 9.
| Factors | Sum of Factors |
|---|---|
| 1 and 18 | 19 |
| -1 and -18 | - 18 |
| 2 and 9 | 11 |
| -2 and - 9 | - 11 |
| 3 and 6 | 9 |
| -3 and - 6 | - 9 |
We found the factors whose product is 18 and whose sum is 9. x^2+9x+18 ⇔ (x+3)(x+6)
Distribute (x+6)
Distribute x
Distribute 3
Add terms
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!