Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
6. Trigonometric Ratios
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Exercise 61 Page 651

Try to rewrite a trinomial as a product of two binomials.

(x+3)(x+6)

Practice makes perfect
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2+9x+18 In this case, we have 18. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same signs - both positive or both negative.
Factor Constants Product of Constants
1 and 18 18
-1 and -18 18
2 and 9 18
-2 and - 9 18
3 and 6 18
-3 and - 6 18

Next, let's consider the coefficient of the linear term. x^2+9x+18 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 9.

Factors Sum of Factors
1 and 18 19
-1 and -18 - 18
2 and 9 11
-2 and - 9 - 11
3 and 6 9
-3 and - 6 - 9
We found the factors whose product is 18 and whose sum is 9. x^2+9x+18 ⇔ (x+3)(x+6)

Checking Our Answer

Check your answer âś“
We can check our answer by applying the Distributive Property and comparing the result with the given expression.
(x+3) (x + 6)
x (x+6) +3 (x + 6 )
x^2 + 6x +3 (x + 6)
x^2 + 6x +3x + 18
x^2+9x+18
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!