Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Trigonometric Ratios
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Exercise 36 Page 650

Practice makes perfect
a We are asked to find the values of each pair of expressions. To do this, we will use a calculator.
First Pair (i) Second Pair (ii)
sin(80^(∘))≈ 0.9848
cos(10^(∘))≈ 0.9848
cos(25^(∘))≈ 0.9063
sin(65^(∘))≈ 0.9063
b Examining the values from Part A, we can notice that the values of sine and cosine in each pair are the same.
First Pair (i) Second Pair (ii)
sin(80^(∘))≈ 0.9848
cos(10^(∘))≈ 0.9848
cos(25^(∘))≈ 0.9063
sin(65^(∘))≈ 0.9063

Moreover, the sum of the angle measures in each pair is equal to 90^(∘).

First Pair (i) Second Pair (ii)
sin( 80^(∘))≈ 0.9848
cos( 10^(∘))≈ 0.9848
cos( 25^(∘))≈ 0.9063
sin( 65^(∘))≈ 0.9063
80^(∘)+ 10^(∘)=90^(∘) 25^(∘)+ 65^(∘)=90^(∘)

This allows us to conclude that the angles in each pair are complementary angles.

c Let's begin by recalling the definitions of sine and cosine.
Term Definition Ratio
Sine The ratio between the lengths of the opposite side and the hypotenuse in a right triangle for a specific angle. sin(θ)=opposite/hypotenuse
Cosine The ratio between the lengths of the adjacent side and the hypotenuse in a right triangle for a specific angle. cos(θ)=adjacent/hypotenuse

Next, we will consider an arbitrary right triangle △ ABC.

By the Triangle Angle Sum Theorem, the sum of the measures of the angles of a triangle is 180^(∘). m∠ A+m∠ B+m∠ C=180^(∘) Since m∠ C is a right angle, we can substitute its measure with 90^(∘). m∠ A+m∠ B+ 90^(∘)=180^(∘) ⇓ m∠ A+m∠ B=90^(∘) Therefore, no matter what measures ∠ A and ∠ B have, they will always be complementary angles. Let's find and analyze the ratios for sin A and cos B.
As we can see, the ratios of sine and cosine for these angles are the same. Therefore, the following relationship between the sine and cosine of two complementary angles is true. sin A=cos B This explains why the results from Part A make sense.