McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Study Guide and Review
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Exercise 34 Page 534

3sqrt(7)

Practice makes perfect

Let's analyze the given rhombus. Recall that the diagonals of a rhombus are perpendicular.

Notice that â–ł ABE is a right triangle. To find the length of AE we can use the Pythagorean Theorem. AE^2 + EB^2 = AB^2 We already know that AB = 12 and EB = 9. Let's substitute these values into the above equation and solve for AE.
AE^2 + EB^2 = AB^2
AE^2 + 9^2 = 12^2
AE^2 + 81 = 144
AE^2 = 63
AE = sqrt(63)
â–Ľ
Simplify
AE = sqrt(9(7))
AE=3sqrt(7)
When solving the equation, we only considered the principal root because AE is the length of a segment and therefore must be positive.