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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Study Guide and Review

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Exercise 33 Page 533

Opposite sides of a rectangle are congruent.

6

Practice makes perfect

Let's analyze the given quadrilateral to find the length EF. Keep in mind that we have been told that the figure is a rectangle.

Recall that opposite sides of a rectangle are congruent. Therefore the lengths of sides EF and HG are equal. EF = HG ⇔ 4x - 6 = x + 3 Let's solve this equation for x.

4x - 6 = x + 3

LHS+6=RHS+6

4x = x + 9

LHS-x=RHS-x

3x = 9

.LHS /3.=.RHS /3.

x = 3

Now, let's use the value of x to find EF.

EF = 4x - 6

x= 3

EF = 4( 3) - 6

Multiply

EF = 12 - 6

Subtract term

EF = 6

Subchapter links

1 Angles of Polygons p.532

2 Parallelograms p.532

3 Tests for Parallelograms p.533

4 Rectangles p.533

5 Rhombi and Squares p.534

6 Trapezoids and Kites p.534