McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. The Triangle Inequality
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Exercise 40 Page 451

Use the Distance Formula to calculate the lengths of the segments formed by the given points.

No, see solution.

Practice makes perfect

We will begin with calculating the lengths of the segments formed by the given points. Let's use the Distance Formula. d=sqrt((x_2-x_1)^2+(y_2-y_1)^2) We can calculate the lengths of JK, KL, and JL by substituting the coordinates of the given points into this formula.

Points Substitute Simplify Segment Length
J(- 7,- 1) and K(9,- 5) JK=sqrt((9-(- 7))^2+(- 5-(- 1))^2) JK=sqrt(256+16) JK≈ 16.5
K(9,- 5) and L(21,- 8) KL=sqrt((21-9)^2+(- 8-(- 5))^2) KL=sqrt(144+9) KL≈ 12.4
J(- 7,- 1) and L(21,- 8) JL=sqrt((21-(- 7))^2+(- 8-(- 1))^2) JL=sqrt(900+49) JL≈ 30.8

Now, let's recall what the Triangle Inequality Theorem states. The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. We can add each pair of two lengths of the sides and compare the sum with the length of the third side.

Chose Two Sides Sum Third Side Comparison
JK and KL 16.5+12.4=28.9 JL=30.8 28.9 < 30.8
KL and JL 12.4+30.8=43.2 JK=16.5 43.2 > 16.5
JK and JL 16.5+30.8=47.3 KL=12.4 47.3 > 12.4

We can see that the theorem is not satisfied for the first pair of sides. Therefore, the given coordinates are not the vertices of a triangle.