Now, we consider a point C on the perpendicular bisector. This point satisfies that AC=BC. Next, we will move this point up so that AC> 2 in. Using a protractor, we can find the measure of ∠A and ∠B.
We have drawn the first required triangle. Doing a similar process we can draw the second triangle, just keep in mind that AB must be the longest side. As an example, below we show two possible isosceles triangles.
Notice that this is just one way to draw the required triangles, and so your answer may vary.
