McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Geometric Probability
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Exercise 34 Page 904

Practice makes perfect
a To find the probability that Meleah will have to wait 5 minutes or less to see each van, we will use geometric probability. Let's model this situation using a coordinate grid. The x-axis will represent the time until Meleah sees the van for company B, and the y-axis will represent the time until she sees the van for company A.

Since the van for company A arrives every 7 minutes, it will arrive in at most 7 minutes. Likewise, since the van for company B arrives every 12 minutes, it will arrive in at most 12 minutes.

The sample space in our model is represented by a rectangle with width 12 and length 7. Let's calculate its area A.
A = l w
A = ( 7)( 12)
A = 84
The outcomes where both vans appear in 5 minutes or less are represented by points with both coordinates less than or equal to 5.
The event that Meleah will have to wait for 5 minutes or less to see each van is represented by a square with side length 5. Let's calculate the area A_S of this square. A_S = 5^2 ⇒ A_S = 25 The probability that Meleah will have to wait 5 minutes or less is the ratio of the area A_S of the region representing the outcomes where Meleah has to wait 5 minutes or less to see each van to the area A of the region representing the sample space.
P(5minutes or less to each van) = A_S/A
P(5minutes or less to each van) = 25/84
P(5minutes or less to each van) = 0.2976619...
P(5minutes or less to each van) ≈ 0.30
P(5minutes or less to each van) ≈ 30 %
The probability that Meleah will have to wait for 5 minutes or less to see each van is 2584, which can be written as a decimal as approximately 0.30, or approximately 30 %.
b To find the probability that Meleah will have to wait 5 minutes or less to see one of the vans, we will use geometric probability. Let's model this situation using a coordinate grid, like we did in Part A.
The outcomes where at least one of the vans appear in 5 minutes or less are represented by points with either coordinate less than or equal to 5.

The event that Meleah will have to wait 5 minutes or less for either van is represented by a region that consists of two rectangles and a square. The square has side length 5, one of the rectangles has length 5 and width 2, and the other rectangle has length 7 and width 5. Let's calculate the areas of these figures.

Length Width Area
Square 5 5 25
Rectangle 1 5 2 10
Rectangle 2 7 5 35
The area A_R of the entire region is the sum of the areas of the square and the two rectangles. A_R = 25+10+35 ⇒ A_R = 70 Now, let's use geometric probability. The probability that Meleah will have to wait 5 minutes or less to see one of the vans is the ratio of the area A_R of the region representing this event to the area A of the region representing the sample space. We know from Part A that A is equal to 84.
P(5minutes or less to any van) = A_R/A
P(5minutes or less to any van) = 70/84
P(5minutes or less to any van) = 0.833333...
P(5minutes or less to any van) ≈ 0.83
P(5minutes or less to any van) ≈ 83 %
The probability that Meleah will have to wait 5 minutes or less for one of the vans is 7084, which can be written as a decimal as approximately 0.83, or approximately 83 %.
c We want to consider a situation where the van for company B arrives before the van for company A and decide whether Meleah should wait for the van for company A. Let's model our situation using a coordinate grid, like we did in Part A.

Since in this case the van for company B arrives before the van for company A, we will only consider the points where the x-coordinate is less than the y-coordinate.

Here, the sample space is represented by a right triangle with legs of length a = 7 and b = 7. Let's calculate the area A of this region.
A = 1/2 ab
A = 1/2 ( 7)( 7)
A = 24.5
Now let's consider the situations where Meleah should wait for the van for company A. If the van for company A will arrive in less than 5 minutes Meleah will not be late, so she should wait. This situation is represented by the points with the y-coordinate less than or equal to 5.

If the van for company B arrives in more than 5 minutes, Meleah runs the risk of being late even if she does not wait, so she should wait as well. This situation is represented by the points with the x-coordinate greater than 5.

Now we will find the area of the shaded region. Note that the shaded region consists of two right triangles: one with both legs of length 5, and another with both legs of length 2. Let's calculate their areas!

Leg Length Area Simplify
5 1/2(5)(5) 12.5
2 1/2(2)(2) 2
The area A_S of the shaded region is the sum of the areas of the triangles. A_S = 12.5 + 2 ⇒ A_S = 14.5 Now we can use geometric probability. The probability that Meleah should wait for the van for company A is the ratio of the area A_S of the shaded region to the area A of the region that represents the sample space.
P(Meleah should wait) = A_S/A
P(Meleah should wait) = 14.5/24.5
P(Meleah should wait) = 0.591837...
P(Meleah should wait) ≈ 0.59
The probability that Meleah should wait for the van for company A is approximately 0.59. Since this leaves a large probability that Meleah will risk being late for the competition, she should not wait for the van for company A.