McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Geometric Probability
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Exercise 40 Page 905

In geometric probability, points on a segment or in a region of a plane represent outcomes. The geometric probability of an event is a ratio that involves geometric measures such as length or area.

C

Practice makes perfect

We can use geometric models to solve certain types of probability problems. In geometric probability, points in a region of a plane represent outcomes. The geometric probability of an event is a ratio that involves geometric measures such as area. Let's first draw a diagram, knowing that a circle is contained inside a square.

We are told that a point in the figure is chosen at random, and want to find the probability that the point in the interior of the square lies in the interior of the circle, which is also the shaded region. The probability that the point is in the shaded region is the ratio of the area of the shaded region to the area of the figure. P(The point is in the shaded region)= [0.8em] Area of the shaded region/Area of the figure

We will find the area of the shaded region and the area of the entire figure one at a time. Then, we will find their ratio.

Area of the Shaded Region

We know that a circle with radius 3 is contained inside a square with a side length equal to 9. Let's first focus on the circle!

Since the radius of the circle is 3, we can substitute this value into the formula for the area of a circle.
A=Ď€ r^2
A=Ď€ ( 3^2)
â–Ľ
Evaluate right-hand side
A=Ď€ (9)
A=9Ď€
The area of the shaded region is 9Ď€. Shaded Area: 9Ď€

Area of the Figure

The figure is a square with a side length equal to 9. To find its area, we need to find the square of the side length. Area of the Figure: 9^2=81

Probability

As previously mentioned, the probability that the point is in the shaded region is the ratio of the area of the shaded region to the area of the figure. Since we already know both areas, we can find their ratio.
P=Area of the shaded region/Area of the figure
P=9Ď€/81
P=Ď€/9
The probability that a point from the figure chosen at random is in the shaded region is π9. This result corresponds to answer C.