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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

6. Secants, Tangents, and Angle Measures

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Exercise 43 Page 767

Use the Midpoint Formula and the fact that AB is a diameter of the circle.

J

Practice makes perfect

Let's draw the points A(-4,8) and B(6,2) and the segment joining them.

To find the coordinates of the center of the circle, we use the fact that since AB is a diameter, its midpoint must be the center of the circle. Midpoint Formula: M = (x_1+x_2/2,y_1+y_2/2) Then, let's substitute the corresponding coordinates into the formula above.

C = (x_1+x_2/2,y_1+y_2/2)

SubstitutePoints

Substitute ( -4,8) & ( 6,2)

C = (-4+ 6/2,8+ 2/2)

▼

Simplify

Add and subtract terms

C = (2/2,10/2)

Calculate quotient

C = (1,5)

In consequence, among the given options the correct one is option J.

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Exercises p.763-767