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Use the Inscribed Angle Theorem and the Triangle Exterior Angle Theorem.
Statements
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Reasons
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1. Tangents RS and RV
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1. Given
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2. m∠VTS = 1/2mSWT m∠STR = 1/2mST
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2. Inscribed Angle Theorem
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3. m∠VTS = m∠RST +m∠R
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3. Triangle Exterior Angle Theorem
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4. 1/2mSWT = 1/2mST +m∠R
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4. Substitution
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5. m∠R = 1/2mSWT -1/2mST
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5. Solving for m∠R
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6. m∠R= 1/2(mSWT - mST)
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6. Factor out 12
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Let's consider a circle and two tangents RS and RV.
By the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of its intercepted arc.
m∠VTS = 12m SWT & (I) m∠STR = 12m ST & (II)
Notice that ∠VTS is an exterior angle of △ STR. Then, applying the Triangle Exterior Angle Theorem, we conclude that its measure is equal to the sum of the measures of the two nonadjacent interior angles.
Given: & TangentsRSand RV Prove: & m∠R = 12(mSWT - mRV) Let's summarize the proof we did above in the following two-column proof table.
Statements
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Reasons
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1. Tangents RS and RV
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1. Given
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2. m∠VTS = 1/2mSWT m∠STR = 1/2mST
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2. Inscribed Angle Theorem
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3. m∠VTS = m∠RST +m∠R
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3. Triangle Exterior Angle Theorem
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4. 1/2mSWT = 1/2mST +m∠R
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4. Substitution
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5. m∠R = 1/2mSWT -1/2mST
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5. Solving for m∠R
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6. m∠R=1/2(mSWT - mST)
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6. Factor out 12
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