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Recall that the angle formed is half the half the measure of the difference of the intercepted arcs.
See solution.
Let's begin by drawing a circle centered at P.
Next, let's draw two lines tangent to the circle.
As we can see, m∠Q = 50^(∘). Now, by the Arc Addition Postulate, we can write the following equation and solve if for one of the measures. mACB + mAB = 360^(∘) ⇓ mAB = 360^(∘) - mACB Now, since the two tangent lines intersect each other outside the circle, the measure of ∠Q is half the measure of the difference of the intercepted arcs. m∠Q = 1/2(mACB - mAB) Let's substitute the expression we found for mAB and m∠Q into the equation above.
m∠Q= 50^(∘), mAB= 360^(∘)-mACB
With this measure, let's find the measure of the minor arc. mAB = 360^(∘) - mACB^(230^(∘)) ⇓ mAB = 130^(∘) To summarize, let's mark all the measures in our diagram.