McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
8. Dilations
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Exercise 36 Page 700

Practice makes perfect
a We are given the coordinates of the vertices of △ ABC.

A(- 2,0), B(2,- 4), and C(4,2) We want to draw the image of △ ABC after the indicated dilations centered at the origin with different scale factors.

  1. A dilation with a scale factor - 2.
  2. A dilation with a scale factor - 12.
  3. A dilation with a scale factor - 3.

    Let's consider each one separately.

    Dilation With a Scale Factor - 2

    To dilate △ ABC by a scale factor of - 2 centered at the origin, we will follow three steps.

    1. Draw a ray from A through the origin and locate A' on AO such that A'O= - 2 AO.
    2. Locate points B' and C' in the same way.
    3. Draw △ A'B'C'.
    Let's do it!

    Dilation With a Scale Factor - 12

    Now, we will draw the dilation of △ ABC centered at the origin with a scale factor of - 12. We will follow similar steps as we did before.

    Dilation With a Scale Factor - 3

    Last, we will dilate △ ABC by a scale factor of - 3. Again, we will follow the exact same steps.
    Let's make a table showing the coordinates of each vertex after dilations.
    Scale Factor Coordinates
    - 2 A'(4,0) B'(- 4,8) C'(- 8,- 4)
    - 1/2 A''(1,0) B''(- 1,2) C''(- 2,- 1)
    - 3 A'''(6,0) B'''(- 6,12) C'''(- 12,- 6)
b We want to make a conjecture about how the coordinates of the vertices of the figure change after a dilation centered at the origin with a negative scale factor. Here are the vertices of △ ABC.
A(- 2,0), B(2,- 4), and C(4,2) Let's then take a look at the table from Part A.
Scale Factor Coordinates
- 2 A'(4,0) B'(- 4,8) C'(- 8,- 4)
- 1/2 A''(1,0) B''(- 1,2) C''(- 2,- 1)
- 3 A'''(6,0) B'''(- 6,12) C'''(- 12,- 6)

If we compare the points with the vertices of △ ABC, we can see that the coordinates of each vertex were multiplied by the scale factor.

Scale Factor Coordinates
- 2 A'( - 2(- 2), - 2(0)) B'( - 2(2), - 2(- 4)) C'( - 2(4), - 2(2))
- 1/2 A''( - 1/2(- 2), - 1/2(0)) B''( - 1/2(2), - 1/2(- 4)) C''( - 1/2(4), - 1/2(2))
- 3 A'''( - 3(- 2), - 3(0)) B'''( - 3(2), - 3(- 4)) C'''( - 3(4), - 3(2))

This is true for any dilation centered at the origin with a negative scale factor - k. This means we can find the coordinates of the image by multiplying each coordinate by - k. (x,y) → ( - kx, - ky)

c Let's recall the function rule for a dilation centered at the origin with a scale factor k. See that here k is a positive value.

(x,y) → (kx,ky) Now, if we take a negative value to be the scale factor, - k, the function rule looks the same. In this rule each coordinate is multiplied by the scale factor. (x,y) → ( - kx, - ky) Notice that it is the same rule as we found in Part B.

d In Parts B and C, we derived the function rule for a dilation centered at the origin with a negative scale factor - k.
(x,y) → (- kx,- ky) Let's rewrite this transformation as a composition of transformations.

(x,y) * k ⟶ (kx,ky) * - 1 ⟶ (- kx,- ky) Here is what each operation means.

  1. Multiplying the x- and y-coordinates by k means a dilation centered at the origin with a scale factor k.
  2. Multiplying the x- and y-coordinates of the points by - 1 means a 180 ^(∘) rotation about the origin.
We can also see the composition of these two transformation in the applet below.
Therefore, the dilation of a figure centered at the origin with a scale factor of - k is the same as a dilation with center at the origin and scale factor k followed by a rotation 180^(∘) about the origin.