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| 13 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Although not directly used, it can be useful to recall the properties of reflections, rotations, and translations to help identify the differences and similarities of rigid motions and dilations.
On the image you can see a photograph taken in Tennoji Park in Osaka, Japan.
When the vertical slider is moved on the previous applet, the transformation applied to the figure is called a dilation.
OA′=k⋅OA⇔k=OAOA′
The following applet shows the images of points on a straight line. There are two modes in the applet, Setup
and Mark image
— complete the first to reach the next.
This applet shows the distance of two points (middle blue points) and the corresponding image points (further right green points).
The following is a list of a few essential properties of dilations.
The formal proof of this property is beyond the scope of this course. The applet below, however, gives an experimental verification.
The formal proof of this property is beyond the scope of this course. The applet below, however, gives an experimental verification.
Let ∠B′A′C′ be the dilated image of ∠BAC. According to the first property, AC is parallel to A′C′ and AB is parallel to A′B′
Let M be the intersection point of AB and A′C′, and focus on the parallel legs AC and A′C′. According to the Alternate Interior Angles Theorem, angles ∠MAC and ∠AMA′ are congruent.
Similarly, since the other legs are also parallel, angles ∠B′A′M′ and ∠AMA′ are congruent.
Since ∠AMA′ is congruent to both ∠BAC and ∠B′A′C′, the transitive property of congruence implies that these two angles are congruent.
By the definition of congruence, this completes the proof that dilation preserves angle measures.
On the applet below you can experiment with dilations.
Consider the quadrilateral ABCD and the point O in the interior.
For both parts, the properties of dilation guarantee that the image is a quadrilateral, where the vertices are the images of the vertices of a quadrilateral ABCD. These image vertices are on the rays connecting the center of dilation with vertices A, B, C, and D.
The larger logo is an enlarged image of the smaller one.
Scale factor: 1.6
Look for pairs of corresponding points on the two logos.
The center of dilation, a point, and the image of this point are on a straight line. Therefore, the center of dilation can be determined to be the intersection point of any two lines connecting a point and its image.
A ruler can be used to find the distance of any point and its image from the center of dilation.
Use the origin as a center to dilate the triangle by a scale factor 2.
Use horizontal and vertical movements to copy distances.
The points on the coordinate axes stay on the coordinate axes while their distances, from the origin, double.
When moving the third vertex, notice that moving three units to the right and two units up from the origin gives the position of B. The same movement starting at B will end on the ray connecting the origin with B. This image point is twice as far from the origin as the preimage.
Connecting the images of the vertices gives the dilated triangle.
The methods to construct the image of a point depend on the scale factor.
Use a compass to measure the distance from the center of dilation to the preimage point.
To construct the image when the scale factor is 1/n, the properties of dilation can be used.
Use a straightedge to connect the center of dilation with the preimage point and draw a second ray starting at the center of dilation.
Use a compass to copy the same distance n times on the second ray, starting at the center of dilation. The diagram illustrates the process when n=3.
Mark the first and last point on the second ray. Connect the last point with the preimage point and construct a parallel line through the first point.
The combination of the previous two methods gives the dilation of a point by a scale factor p/q.
Depending on the scale factor, choose the appropriate method to construct the image of the vertices.
Segments are drawn between the image vertices to create the image polygon.
The following applet allows you to investigate the effect of applying two dilations one after the other. Use the sliders to adjust the scale factors and move the centers around.
Notice that the combination of the two dilations can be replaced by one dilation.
In the following diagram, the larger triangle is a dilation of the smaller triangle.
To determine the value of x, we must equate the side marked (x+ 37) in the original triangle with the side marked (2x+9) in the dilated triangle and then solve for x. However, to do that we must first determine the scale factor of dilation.
The scale factor of dilation can be determined by using the following formula. k= Distance to imageDistance to preimage From the diagram, we know that the distance from the center of dilation to the preimage is 2. The corresponding length from the center of dilation to the image is 7. With this information, we can determine the scale factor. k= 7 2 Any side in the larger triangle is 72 times greater than the corresponding side in the smaller triangle.
With this information, we can write an equation. 7 2 (x+3/7)= 2x+9 Let's solve this equation for x.
To find the length of the side marked 2x+9, we substitute 5 for x in the expression and evaluate. 2( 5)+9 ⇔ 19 cm
Note that a dilation is a similarity transformation, which means it preserves the shape of the original figure. Therefore, the angle marked (y+18)^(∘) has the same measure as the angle marked (3y-34)^(∘). This means we can equate their measures. 3y-34=y+18 Let's solve for y.
We now want to find the measure of the angle marked (3y-34)^(∘). Let's substitute 26 for y in the expression and evaluate. (3( 26)-34)^(∘) ⇔ 44^(∘)
Let's start by graphing △ ABC in a coordinate plane along with the center of dilation, which we will label P.
To dilate this triangle by a factor of 3, the points on the image must be three times as far away from the center of dilation compared to the corresponding points on the preimage. Notice that C needs to be dilated in both the vertical and horizontal directions.
As we can see C' has the coordinates (17,9).
Is XYZW a dilation of ABCD? Explain your reasoning.
We can determine if XYZW is a dilation of ABCD by drawing lines between, what would be, corresponding vertices. If they all converge at one point, that point would be the center of dilation and we have a dilation.
As we can see, the four lines between corresponding vertices do not converge at one point. Therefore, XYZW can not be a dilation of ABCD.
Use a compass to dilate the segment XY with a scale factor of 4 and with X as the center of dilation.
To dilate the segment, we can measure the distance between X and Y with a compass. Open the compass until it measures the width of XY.
Keeping the compass setting intact, use the compass to copy this distance four times from Y.
Finally, we will use a straightedge to draw the dilated segment.
As we can see, the point falls in section 4.