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| 12 Theory slides |
| 7 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Every function has an inverse relation. If this inverse relation is also a function, then it is called an inverse function. In other words, the inverse of a function f is another function f-1 such that they undo each other.
f(f-1(x))=xandf-1(f(x))=x
Also, if x is the input of a function f and y its corresponding output, then y is the input of f-1 and x its corresponding output.
f(x)=y⇔f-1(y)=x
Definition of First Function | Substitute Second Function | Simplify | |
---|---|---|---|
f(f-1(x))=?x | 2f-1(x)−3=?x | 2(2x+3)−3=?x | x=x ✓ |
f-1(f(x))=?x | 2f(x)+3=?x | 22x−3+3=?x | x=x ✓ |
Therefore, f and f-1 undo each other. The graphs of these functions are each other's reflection across the line y=x. This means that the points on the graph of f-1 are the reversed points on the graph of f.
Kriz enjoys playing video games with their friends. For their birthday they received a copy of Mathleaks: The Adventure,
a math-based video game.
Graph:
Are f and g Inverse Functions? Yes.
Graph both functions on the same coordinate plane and see if they are each other's reflection across the line y=x.
Since f and g are linear functions written in slope-intercept form, they can both be graphed using their slope and y-intercept.
It was discussed previously that if the graphs of two functions are each other's reflection across y=x, then they are inverse functions. Therefore, it can be determined if two functions are inverse just by looking at their graphs. Determine whether the following linear functions are inverse by looking at the lines.
If Paulina gets an A on a math test, her mother will buy her a new saxophone.
To get an A, Paulina must answer two questions correctly. Help her get the new saxophone!
g(x)=51x−2
Distribute 5
Associative Property of Multiplication
5⋅5a=a
Multiply
Add terms
Definition of First Function | Substitute Second Function | Simplify | |
---|---|---|---|
f(g(x)) | f(g(x))=5g(x)+10 | f(g(x))=5(51x−2)+10 | f(g(x))=x |
g(f(x)) | g(f(x))=51f(x)−2 | g(f(x))=51(5x+10)−2 | g(f(x))=x |
It has been found that both f(g(x)) and g(f(x)) are equal to x. Therefore, f and g are inverse functions.
Definition of First Function | Substitute Second Function | Simplify | |
---|---|---|---|
h(k(x)) | h(k(x))=21k(x)+6 | h(k(x))=21(2x−6)+6 | h(k(x))=x+3 |
k(h(x)) | k(h(x))=2h(x)−6 | k(h(x))=2(21x+6)−6 | k(h(x))=x+6 |
It has been found that neither h(k(x)) nor k(h(x)) is equal to x. Therefore, h and k are not inverse functions.
For the functions f and g, use a composition to determine whether they are inverse functions.
LHS⋅3=RHS⋅3
LHS+1=RHS+1
LHS/2=RHS/2
Rearrange equation
Zosia lives in Honolulu, Hawaii.
Start by replacing f(x) with y. After that, switch the x- and y-variables. Then, solve the obtained equation for y. Finally, replace y with f-1(x).
To find the inverse of the function, there are four steps to follow.
These steps will be done one at a time.
LHS−24=RHS−24
LHS⋅(-43)=RHS⋅(-43)
Distribute (-43)
Commutative Property of Multiplication
a(-b)=-a⋅b
a⋅cb=ca⋅b
Calculate quotient
a−(-b)=a+b
Rearrange equation
Find the inverse of the given function. Write the answer in slope-intercept form — in the format y=mx+b. If the slope and y-intercept are not integers, express them as decimal numbers. If necessary, round them to two decimal places.
Start by replacing f(x) with y. After that, switch the x- and y-variables. Then, solve the obtained equation for y, and finally replace y with f-1(x).
To find the inverse of the function, there are four steps to follow.
These steps will be done one at a time.
Let's find the equation for g(x) first. Then, we can find the inverse function.
We are told that the slope of g(x) is 5. With this information, we can write a partial equation for g(x). g(x)= 5x+b Here, b is the y-intercept. We know that the graph of g^(-1)(x) passes through ( 15, 1). Since the graphs of two inverse functions are each other's reflections across the line y=x, the graph of g(x) passes through ( 1, 15). Let's substitute these coordinates into the partial equation for g(x). This way, we will find the value of b.
Now we can write the equation for g(x). g(x)=5x+10
To find g^(-1)(x), we can begin by replacing g(x) with y. g(x)=5x+10 replace y=5x+10 Now, we can switch y and x in the equation. cc Equation & Inverse y=5 x+10 & x=5 y+10 Next, we will solve the equation for y to find the inverse function.
Finally, we replace y with g^(-1)(x). g^(-1)(x)=1/5x-2 Let's check if the graph of the inverse function we obtained passes through ( 15, 1).
We got a true statement. Therefore, we found the correct equation for g^(-1)(x)!
Let's start by considering the second piece of information we are given. f^(- 1)(12)=3 This means that when x=12, the value of f^(-1) is 3. It also means that the graph of f^(-1)(x) passes through the point with coordinates ( 12, 3). Recall that the graphs of two inverse functions are each other's reflection across the line y=x. Therefore, if we exchange these coordinates, we have the coordinates of a point that lies on the graph of f(x). ccc Point off^(- 1)(x) & & Point off(x) ( 12, 3) & swap & ( 3, 12) Therefore, the graph of f(x) passes through the point with coordinates (3,12).
We see in the diagram that the points with coordinates (3,12) and (12,3) are each other's reflection across the line y=x! Let's now consider the first piece of information. This is a partial equation for f(x). f(x)=2x+b We already know that the graph of f(x) passes through ( 3, 12). This means that we can find the value of b by substituting x= 3 and f(x)= 12 in the above equation!
We found that b is equal to 6. With this information, we can write the equation for f(x). f(x)=2x+6