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| Student Learning Objectives: |
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inverse function. The lesson provides a step-by-step guide on how to determine if two functions are inverses of each other, both algebraically and graphically. It highlights the significance of the line y=x, as the graphs of two inverse functions reflect across this line. The inverse essentially
undoesthe function, reversing its operations. This knowledge is pivotal for various applications, including real-world scenarios like currency conversion.
| | 12 Theory slides |
| | 7 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Consider a function f that takes any real number and returns a number greater by two units.
An inverse relation is a relation that interchanges the input and output values of a specific relation. In other words, it is the relation that undoes a certain relation. Consider the mapping diagram that shows a relation p that takes elements from set A and returns elements from set B.
The relation that undoes p is q. In this case, q takes elements from set B and returns elements from set A. Relations can also be represented by a collection of ordered pairs. Here, the inverse of a relation is obtained by interchanging the elements of the ordered pairs of the original relation. Relationp {( - 1, C),( 0, E),( 5, Z),( 10, W),( 20, Q)} [1em] Inverse Relationq {( C, - 1),( E, 0),( Z, 5),( W, 10),( Q, 20)} Graphically, the inverse of a relation is a reflection across the line y=x.
Every function has an inverse relation. If this inverse relation is also a function, then it is called an inverse function. In other words, the inverse of a function f is another function f^(- 1) such that they undo each other.
f(f^(- 1)(x))=x and f^(- 1)(f(x))=x
Therefore, f and f^(-1) are inverses of each other. Also, if x is the input of a function f and y its corresponding output, then y is the input of f^(- 1) and x its corresponding output.
f(x)=y ⇔ f^(- 1)(y)=x
Consider a function f and its inverse f^(- 1). f(x)=2x-3 and f^(-1)(x)= x+32
f^(- 1)(x)= x+3/2
2 * a/2= a
Remove parentheses
Subtract term
A similar procedure can be performed to show that f^(- 1)(f(x))=x.
| Definition of First Function | Substitute Second Function | Simplify | |
|---|---|---|---|
| f(f^(- 1)(x))? =x | 2f^(- 1)(x)-3? =x | 2( x+3/2)-3? =x | x=x ✓ |
| f^(- 1)(f(x))? =x | f(x)+3/2? =x | 2x-3+3/2? =x | x=x ✓ |
Therefore, f and f^(- 1) undo each other. The graphs of these functions are each other's reflection across the line y=x. This means that the points on the graph of f^(- 1) are the reversed points on the graph of f.
Kriz enjoys playing video games with their friends. For their birthday they received a copy of Mathleaks: The Adventure,
a math-based video game.
Kriz is very close to beating this level. They need to graph the functions given below and determine whether they are inverse functions. f(x)=4x+5 and g(x)=1/4x-5/4 Help Kriz beat the level and get one step closer beating the game by mastering math!
Are f and g Inverse Functions? Yes.
Now, it can be seen whether the lines are each other's reflection across y=x.
The lines are indeed each other's reflection across y=x. Therefore, f and g are inverse functions.
It was discussed previously that if the graphs of two functions are each other's reflection across y=x, then they are inverse functions. Therefore, it can be determined if two functions are inverse just by looking at their graphs. Determine whether the following linear functions are inverse by looking at the lines.
If Paulina gets an A on a math test, her mother will buy her a new saxophone.
To get an A, Paulina must answer two questions correctly. Help her get the new saxophone!
f(x)=5x+10 and g(x)=1/5x-2 The composite function f(g(x)) will be found first. To do so, the definition of f will be used. f(g(x))=5g(x)+10 Next, g(x)= 15x-2 can be substituted in the above equation.
g(x)= 1/5x-2
Distribute 5
Associative Property of Multiplication
5 * a/5= a
Multiply
Add terms
By following the same procedure, an expression for g(f(x)) can be found.
| Definition of First Function | Substitute Second Function | Simplify | |
|---|---|---|---|
| f(g(x)) | f(g(x))=5g(x)+10 | f(g(x))=5( 1/5x-2)+10 | f(g(x))=x |
| g(f(x)) | g(f(x))=1/5f(x)-2 | g(f(x))=1/5( 5x+10)-2 | g(f(x))=x |
It has been found that both f(g(x)) and g(f(x)) are equal to x. Therefore, f and g are inverse functions.
h(x)=1/2x+6 and k(x)=2x-6 By following the same procedure as in Part A, the expressions for h(k(x)) and k(h(x)) will be found.
| Definition of First Function | Substitute Second Function | Simplify | |
|---|---|---|---|
| h(k(x)) | h(k(x))=1/2k(x)+6 | h(k(x))=1/2( 2x-6)+6 | h(k(x))=x+3 |
| k(h(x)) | k(h(x))=2h(x)-6 | k(h(x))=2( 1/2x+6)-6 | k(h(x))=x+6 |
It has been found that neither h(k(x)) nor k(h(x)) is equal to x. Therefore, h and k are not inverse functions.
For the functions f and g, use a composition to determine whether they are inverse functions.
A function can be represented by a table of values, a graph, a mapping diagram, or a function rule, among other ways. Depending on how the function is presented, finding its inverse can be done in different ways. When a function rule is given, finding the inverse algebraically is advantageous. Consider the following example function. f(x)= 2x-1/3 There is a series of steps to follow in order to find the inverse function f^(- 1)(x).
LHS * 3=RHS* 3
LHS+1=RHS+1
.LHS /2.=.RHS /2.
Rearrange equation
Zosia lives in Honolulu, Hawaii.
She is obsessed with math. While watching a surfer catch some gnarly waves, she came up with a function that models the distance of the surfer from the shore. f(x)=- 4/3x+24 Here, f(x) is the distance of the surfer from the shore after x seconds of riding a wave. Given the distance from shore, Zosia now wants to finds the function that gives the time, in seconds, the surfer has been riding a wave. To do so, she needs to find f^(- 1), the inverse of f. Help Zosia find this function! Write the answer in slope-intercept form.
These steps will be done one at a time.
Here, the variable y will be substituted for f(x) in the given function. f(x)=- 4/3x+24 → y=- 4/3x+24
In this step, the variables x and y must be switched. y=- 4/3 x+24 switch x=- 4/3 y+24
Here, the equation obtained in the previous step will be solved for y.
LHS-24=RHS-24
LHS * (- 3/4)=RHS* (- 3/4)
Distribute (- 3/4)
Commutative Property of Multiplication
a(- b)=- a * b
a*b/c= a* b/c
Calculate quotient
a-(- b)=a+b
Rearrange equation
Finally, f^(- 1)(x) will be substituted for the y-variable in the equation obtained in the previous step. y=- 3/4x+18 ↓ f^(- 1)(x)=- 3/4x+18
Find the inverse of the given function. Write the answer in slope-intercept form — in the format y=mx+b. If the slope and y-intercept are not integers, express them as decimal numbers. If necessary, round them to two decimal places.
In this lesson, it has been seen that the function that undoes a function f is its inverse f^(- 1). Consider the function given in the challenge presented at the beginning of the lesson.
These steps will be done one at a time.
Here, the variable y will be substituted for f(x) in the given function. f(x)=x+2 substitute y=x+2
In this step, the variables x and y must be switched. y= x+2 switch x= y+2
Here, the equation obtained in the previous step will be solved for y. x=y+2 ⇔ y=x-2
Finally, f^(- 1)(x) will be substituted for the y-variable in the equation obtained in the previous step. y=x-2 substitute f^(- 1)(x)=x-2 It has been found that the inverse function of f(x)=x+2, and therefore the function that undoes it, is f^(- 1)(x)=x-2
A linear function g(x) has a slope of 5. The point with coordinates (15,1) is on the graph of its inverse function g^(- 1)(x). Find the function rule of g^(- 1)(x).
Let's find the equation for g(x) first. Then, we can find the inverse function.
We are told that the slope of g(x) is 5. With this information, we can write a partial equation for g(x). g(x)= 5x+b Here, b is the y-intercept. We know that the graph of g^(-1)(x) passes through ( 15, 1). Since the graphs of two inverse functions are each other's reflections across the line y=x, the graph of g(x) passes through ( 1, 15). Let's substitute these coordinates into the partial equation for g(x). This way, we will find the value of b.
Now we can write the equation for g(x). g(x)=5x+10
To find g^(-1)(x), we can begin by replacing g(x) with y. g(x)=5x+10 replace y=5x+10 Now, we can switch y and x in the equation. cc Equation & Inverse y=5 x+10 & x=5 y+10 Next, we will solve the equation for y to find the inverse function.
Finally, we replace y with g^(-1)(x). g^(-1)(x)=1/5x-2 Let's check if the graph of the inverse function we obtained passes through ( 15, 1).
We got a true statement. Therefore, we found the correct equation for g^(-1)(x)!
Let f(x) be a function and f^(- 1)(x) its inverse. The following information is given. f(x)& =2x+b [0.5em] f^(- 1)(12)& =3 Find the value of b.
Let's start by considering the second piece of information we are given. f^(- 1)(12)=3 This means that when x=12, the value of f^(-1) is 3. It also means that the graph of f^(-1)(x) passes through the point with coordinates ( 12, 3). Recall that the graphs of two inverse functions are each other's reflection across the line y=x. Therefore, if we exchange these coordinates, we have the coordinates of a point that lies on the graph of f(x). ccc Point off^(- 1)(x) & & Point off(x) ( 12, 3) & swap & ( 3, 12) Therefore, the graph of f(x) passes through the point with coordinates (3,12).
We see in the diagram that the points with coordinates (3,12) and (12,3) are each other's reflection across the line y=x! Let's now consider the first piece of information. This is a partial equation for f(x). f(x)=2x+b We already know that the graph of f(x) passes through ( 3, 12). This means that we can find the value of b by substituting x= 3 and f(x)= 12 in the above equation!
We found that b is equal to 6. With this information, we can write the equation for f(x). f(x)=2x+6