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{{ printedBook.courseTrack.name }} {{ printedBook.name }} To determine the error, we will find the vertex by ourselves. To do so, we will first express the quadratic function in vertex form, $y=a(x−h)_{2}+k,$ where $a,$ $h,$ and $k$ are either positive or negative constants. $y=-(x+5)_{2}⇔y=-1(x−(-5))_{2}+0 $ Let's compare the general formula for the vertex form with our equation. $General formula:y=Equation:y= -a(x−-(h)_{2}+k-1(x−(-5))_{2}+0 $ We can see that $a=-1,$ $h=-5,$ and $k=0.$ The vertex of a quadratic function written in vertex form is the point $(h,k).$ Therefore, the vertex of this parabola is $(-5,0).$ Let's now examine the given solution.

We see that the value of $h$ was found correctly. However, the interpretation of the vertex form is **not** correct. Based on our operations at the beginning, we can correct the solution as follows.