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y=a(x−p)(x−q)
Here, a, p, and q are real numbers with a=0. The value of a gives the direction of the parabola. When a>0, the parabola faces upward, and when a<0, it faces downward. The zeros of the parabola are p and q, and the axis of symmetry is the vertical line x=2p+q.
Consider the graph of y=21(x−7)(x−13).
Comparing the generic factored form with the example function, the values of a, p, and q can be identified.Direction | Zeros | Axis of Symmetry |
---|---|---|
a=21 | p=7 and q=13 | 2p+q ⇓ 27+13=10 |
Since 21 is greater than 0, the parabola opens upward. | The zeros are 7 and 13. Therefore, the parabola intersects the x-axis at (7,0) and (13,0). | The axis of symmetry is the vertical line x=10. |
Function 1 | Function 2 | Function 3 |
---|---|---|
y=2(x+1)(x−3) ⇕ y=2(x−(-1))(x−3) |
y=(x−5)(x−9) ⇕ y=1(x−5)(x−9) |
y=5x(x−2) ⇕ y=5(x−0)(x−2) |