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{{ printedBook.courseTrack.name }} {{ printedBook.name }} We want to identify the vertex and the axis of symmetry of the graph of given quadratic function. To do so, we will first express it in vertex form, $y=a(x−h)_{2}+k,$ where $a,$ $h,$ and $k$ are either positive or negative numbers.
$y=-5(x+12)_{2}⇔y=-5(x−(-12))_{2}+0 $
It is important to note that we do **not** need to graph the parabola to identify the desired information. Let's compare the general formula for the vertex form to our function.
$General formula:y=Equation:y= -a(x−-(h)_{2}+k-5(x−(-12))_{2}+0 $
We can see that $a=-5,$ $h=-12,$ and $k=0.$

The vertex of a quadratic function written in vertex form is the point $(h,k).$ For this exercise, we have $h=-12$ and $k=0.$ Therefore, the vertex of the given equation is $(-12,0).$

The axis of symmetry of a quadratic function written in vertex form is the vertical line with equation $x=h.$ As we have already noticed, for our function, this is $h=-12.$ Thus, the axis of symmetry is the line $x=-12.$