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{{ printedBook.courseTrack.name }} {{ printedBook.name }} We want to find the $x-$intercepts and the axis of symmetry of the given function. Let's do it one at a time.

Recall the factored form of a quadratic function. $y=a(x−p)(x−q) $ In this form, where $a$ $ =$ $0,$ the $x-$intercepts are $p$ and $q.$ Let's consider the factored form of our function. $f(x)=32 x(x+8)⇕f(x)=32 (x−0)(x−(-8)) $ We can see that $a$ $=$ $32 ,$ $p$ $=$ $0,$ and that $q$ $=$ $-8.$ Therefore, the $x-$intercepts are $0$ and $-8.$

The axis of symmetry is halfway between $(p,0)$ and $(q,0).$ Since we know that $p=0$ and $q=-8,$ the axis of symmetry of our parabola is halfway between $(0,0)$ and $(-8,0).$ $x=2p+q ⇒x=20+(-8) =2-8 =-4 $ We found that the axis of symmetry is the vertical line $x=-4.$