Interpreting Quadratic Functions in Factored Form

To match the given function with its graph, we will find its zeros. To do so, we will rewrite it a little bit. $$\begin{array}{c}y=(x-5)(x-3)\iff y=1(x-5)(x-3)\end{array}$$ Note that now the quadratic function is written in factored form. $$\begin{array}{rl}\text{Factored form:}& y=a(x-p)(x-q)\\ \text{Given equation:}& y=1(x-5)(x-3)\end{array}$$ In this form, the zeros of the function are $p$ and $q.$ Therefore, the zeros of the given function are $5$ and $3.$ This matches choice II.