To match the given function with its graph, we will find its zeros. To do so, we will rewrite it a little bit. y=52x(x+5) ⇔ y=52(x−0)(x−(-5)) Note that now the quadratic function is written in factored form. Factored form:Given equation: y=a(x−p)(x−q) y=52(x−0)(x−(-5)) In this form, the zeros of the function are p and q. Therefore, the zeros of the given function are 0 and -5. This matches choice IV.