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$p=-6.25t+100$

Substitute$p=0$

$0=-6.25t+100$

AddEqn$LHS+6.25t=RHS+6.25t$

$6.25t=100$

DivEqn$LHS/6.25=RHS/6.25$

$t=6.25100 $

UseCalcUse a calculator

$t=16$

b

c

We found in Part A that the $x$-intercept is at $16$ minutes. This means that, after $16$ minutes, the percent of the process left to complete will be zero. In other words, the process takes $16$ minutes to complete.

d

We can use the graph in Part B, to find the domain and range of the function.

We see that $t$ can take any value from $0$ to $16,$ inclusive. We also see in the graph that $p$ can take any value between $0$ and $100,$ inclusive. $D:R: 0≤t≤160≤p≤100 $