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| 16 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Consider the following statement.
In the applet, rigid motions can be applied only on △ABC.
Reflectbutton.
In the previous exploration, it was seen that a pair of triangles can have corresponding congruent angles but not be congruent triangles. Therefore, relying only on the relationship of only angles is not a valid criterion.
Angle-Angle-Angle is not a valid criterion for proving triangle congruence.
The previous exploration suggests that two triangles are congruent whenever they have two pairs of corresponding congruent sides and the corresponding included angles are congruent. In fact, this conclusion is formalized in the Side-Angle-Side Congruence Theorem
If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
Based on the diagram above, the theorem can be written as follows.
This proof will be developed based on the given diagram, but it is valid for any pair of triangles.
In the following diagram, triangles ADE and BCE are congruent, and ∠ADC is congruent to ∠BCD.
How many more pairs of congruent triangles are there in the diagram? Name each congruent triangle pair.
Remember, if two triangles are congruent, then their corresponding sides and angles are congruent.
Start by highlighting the given pair of congruent triangles, △ADE and △BCE.
Since these triangles are congruent, their corresponding parts are congruent. This implies that AD is congruent to BC.
△ADC≅△BCD
△ABD≅△BAC
The last two triangles to consider are triangles ABE and DEC. Unlike the first two pairs, these dimensions seem to be quite different. Therefore, it can be concluded that they are not congruent.
Consequently, in the initial diagram, there are two more pairs of congruent triangles in addition to the given one.
Use segment AB and the rays AX and BY to construct two different triangles, one at a time, in such a way that the following conditions are met.
The following statement could be seen in the previous applet. When two triangles have two pairs of corresponding congruent angles, and the included corresponding sides are congruent, the triangles are then congruent. That leads to the second criteria for triangle congruence.
If two angles and the included side of a triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.
Based on the diagram above, the theorem can be written as follows.
This proof will be developed based on the given diagram, but it is valid for any pair of triangles.
Consider the following diagram.
Take note that QS is a common side for two triangles. Use the fact that if two triangles are congruent, their corresponding sides and angles are congruent.
x=1.5
LHS−1.5=RHS−1.5
LHS/2=RHS/2
Use a calculator
Rearrange equation
As seen in the previous exploration, the Side-Side-Side is a valid criterion for checking triangle congruence.
If the three sides of a triangle are congruent to the three sides of another triangle, then the triangles are congruent.
Based on the diagram above, the theorem can be written as follows.
This proof will be developed based on the given diagram, but it is valid for any pair of triangles.
The points C and F′′ are on opposite sides of AB. Now, consider CF′. Let G denote the point of intersection between AB and CF′′.
It can be noted that AC=AF′′ and BC=BF′′. By the Converse Perpendicular Bisector Theorem, AB is a perpendicular bisector of CF′′. Points along the perpendicular bisector are equidistant from the endpoints of the segment, so CG=GF′′.
Given three random segments, it is not always possible to construct a triangle. But, when possible, this triangle will be unique. This fact implies that the angle measures of that triangle are also unique.
In the following diagram, R1 is a rectangle, S1 and S2 are squares, T1, T2, and △MKL are isosceles triangles, DK is congruent to CL, and GM is congruent to JM.
Using the Segment Addition Postulate and the Side-Side-Side (SSS) Congruence Theorem, prove that △DGL is congruent to △CJK. Then, find the measure of ∠JCK. Use the fact that m∠JCK+m∠DCB+m∠JCH+x=360∘.
If △DGL and △CJK can be proven to be congruent, that would provide the needed information to find the value of z. Therefore, focus on those two triangles.
DL≅CK
GL≅JK
Since R1 is a rectangle, S1 and S2 are squares, and T1 and T2 are isosceles triangles, the following consequences can be drawn.
Given | Consequence |
---|---|
R1 is a rectangle | DA≅CB |
S1 is a square | DG≅DE |
S2 is a square | CH≅CJ |
T1 is an isosceles triangle | DE≅DA |
T2 is an isosceles triangle | CB≅CH |
Next, organize the information in the right-hand column in a flow chart and use the Transitive Property of Congruence to prove that DG≅CJ.
Notice that the ASA criterion requires the congruent sides to be included between the two pairs of corresponding congruent angles. Using the following applet, investigate what happens when the congruent sides are not the included sides.
Use segment AB and the rays AX and BY to construct two different triangles, one at a time, in such a way that these conditions are met:
As seen in the previous exploration, the Angle-Angle-Side condition is a valid criterion for triangle congruence.
If two angles and a non-included side of a triangle are congruent to two angles and the corresponding non-included side of another triangle, then the triangles are congruent.
Based on the diagram above, the theorem can be written as follows.
This proof will be developed based on the given diagram, but it is valid for any pair of triangles.
It is given that two angles of △ABC are congruent to two angles of △BCD′′. Hence, by the Third Angle Theorem, ∠BCD′′ is congruent to ∠BCA.
Dylan bought a new boomerang to play with his friends next summer. In the drawing printed on the boomerang, ∠A and ∠C are congruent, and BF and BE are congruent.
Show that AE is congruent to CF.
See solution.
Separate triangles ABE and CBF and notice they have a common angle. Then, use the Angle-Angle-Side (AAS) Congruence Theorem.
With the help of the following applet, investigate if the Side-Side-Angle is a valid criterion for determining triangle congruence.
Use segments AB and AC to construct two different triangles in such a way that the angle formed at B has the same measure in both triangles.With the previous applet, it can be checked that, in general, the Side-Side-Angle is not a valid criterion to determine triangle congruence. For instance, the following triangles meet the conditions of this criterion, and they are not congruent.
However, this criteria is valid in the particular case that both triangles are right triangles.
If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the two triangles are congruent.
Based on the diagram, the following relations hold true.
Consider △ABC and △DEF, shown below.
(II): c2=a2+b12
Therefore, by the Side-Side-Side Congruence Theorem the triangles are congruent.
△ABC≅△DEF
In the following chart, all the criteria for triangle congruence seen in the lesson are listed.
Ignacio says that △ABD is congruent to △CDB by the SSS Congruence Theorem. Paulina says that the triangles are congruent by the HL Congruence Theorem. Who, if either, is correct?
Let's start by explaining the theorems.
From the diagram, we can see that the triangles share their hypotenuse. Therefore, by the Reflexive Property of Congruence, we can claim that the hypotenuses are congruent. Let's add this to the diagram.
Next, by separating the two triangles, it becomes easier to see both Ignacio's and Paulina's points of view.
As we can see, congruence can be proved by both theorems. Therefore, both Ignacio and Paulina are correct.
Are the following triangles congruent? Justify your conclusion with every triangle congruence theorem that is applicable.
Examining the diagram, we can identify two right triangles. Let's introduce some variables to label the unknown sides. Then we can write two equations to find the missing lengths.
Let's solve for the unknown hypotenuse c.
Let's also solve for the unknown leg b.
The unknown leg is 6 units long. Since the two triangles have three pairs of congruent corresponding sides, we know that they are congruent by the Side-Side-Side Congruence Theorem. We could also use the Hypotenuse-Leg Congruence Theorem.
From the diagram, we notice that the triangles have two pairs of congruent angles and one pair of corresponding congruent non-included sides. With this information, we can claim congruence by the Angle-Angle-Side Congruence Theorem.
Examining the diagram, we see that the triangles have a pair of congruent angles and a pair of congruent sides. Additionally, the triangles also share one of their sides. By the Reflexive Property of Congruence, we know that this side is congruent as well. Let's mark this in the diagram.
However, this information does not match any triangle congruence theorem. Therefore, we cannot prove congruence.
Just like in the previous exercise, we have two triangles that share a side. This means this side is congruent according to the Reflexive Property of Congruence. Let's add this to the diagram.
Now we can claim congruence by the Side-Angle-Side Congruence Theorem.
Which triangles are congruent to △A? Select all that apply.
Looking at △ A, we see a couple of things.
Given the information about △ A, we cannot use the Side-Side-Side Congruence Theorem or the Hypotenuse-Leg Congruence Theorem. We are left with three theorems which can be used to prove triangle congruence.
In order to use SAS, two pairs of sides and their included angles must be congruent. Examining the triangles, we see that only △ D fulfills this criteria.
To use ASA or AAS, we need to know two angles and one side, either the included side (ASA) or a non-included side (AAS). Examining the diagram, we see that △ E fulfills the ASA criteria.
The triangles that are congruent to △ A are △ D and △ E.
Are the triangles congruent? If so, justify your answer with a triangle congruence statement.
Examining the diagram, we see three pairs of congruent sides. &AC≅DE &BC≅BE &AB≅DB Since we have three pairs of congruent sides, the triangles are congruent by the Side-Side-Side Congruence Theorem.
Notice that we have not been given any information about the triangle's angles. Therefore, we can only attempt to use the Side-Side-Side Congruence Theorem. From the diagram we can identify a pair of congruent sides. Also, the triangles share QS as a side. Therefore, according to the Reflexive Property of Congruence, this side of the triangles are congruent as well. Let us add that to the diagram.
To prove congruence by the SSS Congruence Theorem, we also need the remaining pair of sides to be congruent. Even though it appears as though PS and RS are congruent, we do not have a way to confirm that they are. Therefore, we cannot claim congruence.
If the hypotenuse and a pair of legs in two right triangles are congruent, then by the HL Congruence Theorem, the triangles are congruent. From the diagram, we can see that the hypotenuses are congruent, and we can also identify a pair of congruent legs. BC ≅ EF AB ≅ DE Since the triangles are both right triangles, we can claim congruence by the HL Congruence Theorem.
Are the triangles congruent? If so, justify your answer with a triangle congruence statement.
Examining the triangles, we can identify two pairs of congruent angles and one pair of non-included congruent sides. Angle:& ∠ E ≅ ∠ A Angle:& ∠ D ≅ ∠ C Side:& DF≅CB As we can see, we have enough information to claim congruence by the AAS Congruence Theorem.
Examining the diagram, we can identify a pair of congruent angles. We can also see that ∠ ACD is a straight angle, and because ∠ BCD is a right angle, ∠ BCA must be a right angle as well. Additionally, BC is a shared side, which means we can claim that this side is congruent according to the Reflexive Property of Congruence.
Let's list everything we know. Angle:& ∠ BAC≅ ∠ BDC Angle:& ∠ BCA ≅ ∠ BCD Side:& BC≅BC As we can see, we can claim congruence by the AAS Congruence Theorem.
From the diagram, we can see that the triangles have two pairs of congruent sides and a pair of congruent non-included angles. Angle:& ∠ F ≅ ∠ C Side:& EF≅AC Side:& ED≅AB There is no congruence theorem that uses two sides and a non-included angle. Therefore, there is not enough information to claim congruence.