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The result of factoring out a GCF from the given expression is a trinomial with a leading coefficient of 1. 2( x^2-x-2) Let's temporarily only focus on this trinomial, and we will bring back the GCF after factoring.
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2-x- 2 In this case, we have -2. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative.)
Factor Constants | Product of Constants |
---|---|
1 and - 2 | - 2 |
-1 and 2 | - 2 |
Next, let's consider the coefficient of the linear term. x^2-1x- 2 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, -1.
Factors | Sum of Factors |
---|---|
1 and - 2 | -1 |
-1 and 2 | 1 |
We found the factors whose product is - 2 and whose sum is -1. x^2-1x-2 ⇔ (x+1)(x-2) Wait! Before we finish, remember that we factored out a GCF from the original expression. To fully complete the factored expression, let's reintroduce that GCF now. 2(x+1)(x-2)
The result of factoring out a GCF from the given expression is a trinomial with a leading coefficient of 1. 4( x^2-6x+9) Let's temporarily only focus on this trinomial, and we will bring back the GCF after factoring.
We want to factor the given expression. Factoring is much easier when our polynomial is a perfect square trinomial. To determine if an expression is a perfect square trinomial, we need to ask ourselves three questions.
Is the first term a perfect square? | x^2= x^2 âś“ |
Is the last term a perfect square? | 9= 3^2 âś“ |
Is the middle term twice the product of 3 and x? | 6x=2* 3* x âś“ |
As we can see, the answer to all three questions is yes! Therefore, we can write the trinomial as the square of a binomial. Note there is an subtraction sign in the middle. ( x^2-6x+9) ⇔ ( x- 3)^2 Wait! Before we finish, remember that we factored out a GCF from the original expression. To fully complete the factored expression, let's reintroduce that GCF now. 4(x-3)^2