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Split the compound inequality into two separate ones and solve them individually.
Solution Set: -3 ≤ a ≤ 2
Graph:
and.-2 ≤ 4-3a and 4-3a ≤ 13
Now we can solve them separately.
LHS-4≤RHS-4
Divide by -3 and flip inequality sign
Rearrange inequality
Note that the point on 2 is closed because it is included in the solution set.
Notice that a can equal -3 as the inequality sign contains or equal to.
The solution set to the compound inequality is the intersection of the solution sets. To help visualize the algebraic expression, we will write a ≥-3 as -3 ≤ a. First Solution Set: a& ≤ 2 Second Solution Set: - 3≤ a& Intersecting Solution Set: - 3≤ a& ≤ 2 Finally, we will graph the solution set to the compound inequality on a number line.