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Solve for x and consider all possible values of a, b, c, and d, including 0, positive values, and negative values.
See solution.
Before we can think about the possible solution sets for x, let's simplify our inequality a little bit so that x is as isolated as possible.
LHS-b
LHS-cx
Factor out x
We cannot go any further just yet. What if a-c=0? What if a-c is a negative number? There are actually four cases we need to consider for this inequality. First case: &a = c and d > b Second case: &a = c and d < b Third case: &a > c Fourth case: &a < c
In the first case, we should consider when a=c and d>b. When a=c we have a-c=0.
(a-c)= 0
Zero Property of Multiplication
With the assumption that d>b we must have that d-b is always a positive number. Therefore, we have 0
In the second case, we should consider when a=c and d
Zero Property of Multiplication
With the assumption that d
In the third case, we should consider when a>c. When a>c, we must have that a-c will always be a positive number in which case we can simply divide and keep the inequality symbol as it is.
.LHS /(a-c).<.RHS /(a-c).
Our solution set is then all values such that
x
In the fourth case, we should consider when a
Divide by (a-c) and flip inequality sign
Our solution set is then all values such that x>d-b/a-c