Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
Chapter Review
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Exercise 22 Page 96

It may be easier to solve the compound inequality as two separate cases.

Solution: - 2 ≤ z ≤ 6
Graph:

Practice makes perfect
To make solving a little bit easier, we can separate the compound inequality into two cases. Compound Inequality: 19 ≥&3z+1≥-5 First Inequality: 19 ≥&3z+1 Second Inequality: &3z+1≥-5 Notice that compound inequalities written in this way are equivalent to compound inequalities that involve the word and. 19 ≥3z+1 and 3z+1≥-5

Let's solve the inequalities separately.

First Inequality

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when you divide or multiply by a negative number, you must flip the inequality sign.
19≥3z+1
â–Ľ
Solve for z
18≥3z
6≥ z
z≤ 6
This above tells us that all values less than or equal to 6 will satisfy the inequality.

Note that the point on 6 is closed because it is included in the solution set.

Second Inequality

Once more we will solve the inequality by isolating the variable.
3z+1≥-5
â–Ľ
Solve for z
3z≥-6
z≥-2
-2 ≤ z
This above tells us that - 2 is less than or equal to all values that satisfy the inequality.

Note that the point on - 2 is closed because it is included in the solution set.

Compound Inequality

The solution set to the compound inequality is the intersection of the solution sets. First Solution Set: z&≤ 6 Second Solution Set: -2 ≤ z& Intersecting Solution Set: - 2≤ z& ≤ 6 Finally, we will graph the solution set to the compound inequality on a number line.