13AddIneqLHS+7>RHS+7 5|b+8|>20DivIneq.LHS'>

Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
Chapter Review
Continue to next subchapter

Exercise 27 Page 96

Create an or compound inequality because the absolute value needs to be greater than or less than the given value.

Solution Set: b< -12 or b>-4
Graph:

Practice makes perfect
We are asked to find and graph the solution set for all possible values of b in the given inequality. 5|b+8|-7>13 To do this, let's isolate absolute value expression first.
5|b+8|-7> 13
5|b+8|>20
|b+8|>4

Now, we can create a compound inequality by removing the absolute value. In this case, the solution set is any number with a distance greater than 4 or less than -4. b+8 > 4 or b+8<-4 Let's isolate b in both of these cases before graphing the solution set.

First Inequality

b+8>4
b>-4
This inequality tells us that all values greater than -4 will satisfy the inequality.

Second Inequality

b+8<-4
b<-12
This inequality tells us that all values less than -12 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the combination of the solution sets. First Solution Set:& b>-4 Second Solution Set:& b<-12 Combined Solution Set:& b<-12 or b>-4

Graph

The graph of this inequality includes all values less than -12 or greater than -4. We show this by keeping the endpoints open.